Given that
![X\sim\mathrm{Unif}(0,5)](https://tex.z-dn.net/?f=X%5Csim%5Cmathrm%7BUnif%7D%280%2C5%29)
, it has PDF
![f_X(x)=\begin{cases}\dfrac15&\text{for }0\le x\l5\\\\0&\text{otherwise}\end{cases}](https://tex.z-dn.net/?f=f_X%28x%29%3D%5Cbegin%7Bcases%7D%5Cdfrac15%26%5Ctext%7Bfor%20%7D0%5Cle%20x%5Cl5%5C%5C%5C%5C0%26%5Ctext%7Botherwise%7D%5Cend%7Bcases%7D)
and thus CDF
![F_X(x)=\mathbb P(X\le x)=\begin{cases}0&\text{for }x](https://tex.z-dn.net/?f=F_X%28x%29%3D%5Cmathbb%20P%28X%5Cle%20x%29%3D%5Cbegin%7Bcases%7D0%26%5Ctext%7Bfor%20%7Dx%3C0%5C%5C%5C%5C%5Cdfrac%20x5%26%5Ctext%7Bfor%20%7D0%5Cle%20x%3C5%5C%5C%5C%5C1%26%5Ctext%7Bfor%20%7Dx%5Cge5%5Cend%7Bcases%7D)
The 25th percentile is the value
![X=k](https://tex.z-dn.net/?f=X%3Dk)
such that
![\mathbb P(X\le k)=0.25](https://tex.z-dn.net/?f=%5Cmathbb%20P%28X%5Cle%20k%29%3D0.25)
. We have
Equal to the area. Area of circle is
![\pi r^2](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E2)
This equals to
![4 \pi](https://tex.z-dn.net/?f=%204%20%5Cpi%20)
due to 2^2.
Circumference is
![2 \pi r](https://tex.z-dn.net/?f=2%20%5Cpi%20r)
This equals to
![2 \pi (2)](https://tex.z-dn.net/?f=2%20%5Cpi%20%282%29)
When you multiply the 2 and the radius together, they equal to 2^2.
Which results to
Letter c I’m 99 percent sure because the angles are the same which therefore means they are congruent
1/4t + 9 = 3
Subtract 9 from both sides
1/2t= -6
Divide 1/2 on both sides so that the only thing remaining on the left side is the variable t.
Final Answer: t= -12