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pshichka [43]
3 years ago
12

Please help ! ALGEBRA 1

Mathematics
2 answers:
aliina [53]3 years ago
8 0

Answer:

Option B is the correct answer.

Step-by-step explanation:

0. \overline{79} +   \pi

Here 0.\overline{79} is a rational number and \pi is an irrational number whose sum gives irrational number.

love history [14]3 years ago
5 0

Answer:

Te answer  would be to tenth of PIE so 0.79 would be ruled out

Step-by-step explanation:

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3 years ago
In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24
Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.238\\H_A: p > 0.238

This is a one-tailed(right) test.  

Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

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