Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
As the sine rule states,
A/sina = B/sinb = C/sinc .
in the diagram, there are two identified sides and if you use the sine rule, you can find the opposed angles easily.
there are:
side a, with angle â .
side b, with angle b.
so the answer is C.
if you input these into the sine rule, it would be:
a/ sin a = b/sin b
Answer: 5(x-1)
Step-by-step explanation:
5*x = 5x
5*-1 = -5
therefore the answer is 5(x-1)
I need another number for this problem to answer