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Ronch [10]
3 years ago
14

HELP ASAP PLEASE THIS QUESTION IS ABOUT FUNCTIONS SO IF U KNOW HOW TO DO FUNCTIONS PLEASE HELP I HAVE ASKED THIS LIKE MAYBE 4 TI

MESSSSS :(
ALSO DONT PUT A RANDOM ANSWER AND TAKE THE POINTS I REALLY NEED HELP

Mathematics
2 answers:
Vikentia [17]3 years ago
6 0

Answer:

range: [-3,-1) domain: [4,-3); idrk know the second one srry.

Step-by-step explanation:

Solnce55 [7]3 years ago
5 0

Answer:

Domain: -3<=x<4

Range:-1<=y<-3

(can I get brainliest please)

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4. An equilateral triangle has a perimeter of 60 cm. Find the exact<br> altitude of the triangle.
taurus [48]

Step-by-step explanation:

<h2>GIVEN:-</h2>

The Perimeter of Equilateral triangle = 60cm

<h2>UNDERSTANDING THE CONCEPT:-</h2>

According to the question,

To find the height of the triangle,

Perimeter of Equilateral triangle = Area of Equilateral triangle.

<h2>FORMULA USED:-</h2>

60 =  \frac{ \sqrt{3} }{4} a {}^{2}  \\

<h2>REQUIRED ANSWER:-</h2>

60 \times 4 =  \sqrt{3a {}^{2} }

a {}^{2}  = 240 \sqrt{3}  \\

a = 120 \sqrt{3} cm

<h3>SO, The Exact height of the triangle is 120√3cm.</h3>
5 0
3 years ago
25% is equivalent to what fraction in reduced terms
marishachu [46]
The solution is 1/4 because 25/100 / 25/25 1/4

8 0
3 years ago
During an experiment, a spinner landed on red 6 times. If the resulting experimental probability of the spinner landing on red i
dem82 [27]

Answer:

Excuse me I need more information to solve this question.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
Can you help me with a rational expressions &amp; eplquations please
nasty-shy [4]
Yes I can help you with rational expressions and eplquations!
4 0
3 years ago
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