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3 years ago

Is the sequence arithmetic..... if so identify the common difference

Mathematics

2 answers:

const2013 [10]3 years ago

8 0

Answer:

A) Yes, 7

Step-by-step explanation:

The given sequence An = {13, 20, 27, 34, ...}

Here the first term Ao = 13 and difference between the successive terms is (d) = 7

That is d = 20 - 13

d = 7

It is an arithmetic sequence. d = 7

Answer: Yes, it is arithmetic sequence and common difference (d) = 7

Thank you.

adell [148]3 years ago

6 0

Answer:

A. Yes, 7 was right :)

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The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?

Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

$N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}$

where,

$N(t)$ = quantity of the substance remaining

$N_0$ = initial quantity of the substance

$t$ = time elapsed

$t_{1/2}$ = half life of the substance

From the information given we know:

The initial quantity of silicone-32 is 30 g.
The time elapsed is 300 years.
The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

$N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g$

22.38 g of silicone-32 will be present in 300 years.

7 0

3 years ago

Given that a function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8, select the st

notka56 [123]

Options

(A)g(5) = 12
(B)g(1) = -2
(C)g(2) = 4
(D)g(3) = 18

Answer:

(D)g(3) = 18

Step-by-step explanation:

Given that the function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8

Then the following properties must hold

The value(s) of x must be between -1 and 4
The values of g(x) must be between 0 and 18.
g(-1)=2
g(2)=9

We consider the options and state why they are true or otherwise.

Option A: g(5)=12

The value of x=5. This contradicts property 1 stated above. Therefore, it is not true.

Option B: g(1) = -2

The value of g(x)=-2. This contradicts property 2 stated above. Therefore, it is not true.

Option C: g(2) = 4

The value of g(2)=4. However by property 4 stated above, g(2)=9. Therefore, it is not true.

Option D: g(3) = 18

This statement can be true as its domain is in between -1 and 4 and its range is in between 0 and 18.

Therefore, Option D could be true.

3 0

4 years ago

Easy points. see image below

tatuchka [14]

Answer:

Given expression:

$\sf -(-(-3)) + 2 + |-7|$

Simplify following inside parenthesis

$\sf -3 + 2 + |-7|$

If following is |-a| then |-a| = a

$\sf -3 + 2 + 7$

Evaluate following

$\sf 6$

4 0

2 years ago

Please help with homework

Sedbober [7]

Ashley should get her seeds at garden place as she gets the exact amount of seeds and spends the least amount of money.
first of all I divided 75 by the amount of seeds you get it a packet. then if that was a decimal I rounded it to the larger number (eg. 7.15 rounded to 8)
then I multiplied the cost by that number to get the amount of money itd cost.
so I got in order of the boxes(s=seeds)
75s=$18
80s=$18.4
84s=$21.84
80s=$20
so the best deal is Garden place

7 0

3 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago