Answer:
see below
Step-by-step explanation:
The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.
The line for x > 2 is the horizontal line x=2.
The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.
Add 1 to both sides:
In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that
Under this assumption, we square both sides and we have
The solutions to this equation are
But since we can only accept solutions greater than -1, we discard and accept
.
In fact, we have
and
which is the only solution.
