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3 years ago

Guys please help me with the equations!!!

Mathematics

1 answer:

Ainat [17]3 years ago

8 0

Answer:

2. x=2; y=5

3. x=3; y=5

4. y=2; x=5

5. x=4; y=3

6. x=3; y=4

7. x=7; y=4

If you get the pattern, you will be able to do the last three

Step-by-step explanation:

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What is the length of segment TQ.

Jobisdone [24]

Answer:

C ) 14 units

Step-by-step explanation:

I am assuming this is the problem's image? If not, please let me know and I will do a different one. I hope this helps!

We know QV = 15 and TQ = TS, QV = SV;

4 x - 1 = 15

4 x = 15 + 1

4 x = 16

x = 16 : 4 = 4

so,

TQ = 3 * 4 + 2 = 12 + 2 = 14

Answer:

C ) 14 units

3 0

2 years ago

Lina eats 2 1/4 blueberries every 8 minutes. How many blueberries does lina eat per minute?

amid [387]

3.5556 blueberrys per minute

8 0

3 years ago

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Match the measures with the correct type of measurement:

r-ruslan [8.4K]

Answer:

72 m = Perimeter

125 mm^3 = Volume

50 cm^2 = Surface Area

7 0

3 years ago

Read 2 more answers

How do I solve this

anastassius [24]

$\bf \cfrac{x+2}{x^2+6x-7}$ so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well, you know, if we end up with a 0 at the denominator, like $\bf \cfrac{x+2}{0}$ then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.

so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

$\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=
\begin{cases}
-7\\
1
\end{cases}
\\\\\\
\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}
\\\\\\
x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}$

7 0

3 years ago

The cost for 5 adults and 3 children to attend a show is $210. ( /5)

liraira [26]

Answer: i. Cost of adult ticket = $ 30

ii. Cost of child ticket = $20

Step-by-step explanation:

Define variables:

Let x= cost of 1 adult tickets , y= cost of 1 child tickets.

Form linear equations:

5x+3y = 210 (i)

2x+5y= 160 (ii)

Multiply (i) by 2 and (ii) by 5

10x +6y = 420 (iii)

10x+25y = 800 (iv)

Eliminate (iii) from (iv)

19y = 380

⇒ y= 20

Put this in (i)

$5x+3(20)=210\Rightarrow\ 5x+60 = 210\\\\\Rightarrow\ 5x=150\\\\\Rightarrow\ x=30$

Hence, Cost of adult ticket = $ 30 and Cost of child ticket = $20

4 0

3 years ago