A box contains 23 transistors,6 of which are defective. If 6 are selected at random, find the probility that none are defective

1 answer:

3 0

$|\Omega|=C(23,6)=\dfrac{23!}{6!17!}=100947\\
|A|=C(17,6)=\dfrac{17!}{6!11!}=12376\\\\
P(A)=\dfrac{12376}{100947}=\dfrac{1768}{14421}$

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