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Margarita [4]
3 years ago
8

A box contains 23 transistors,6 of which are defective. If 6 are selected at random, find the probility that none are defective

?
Mathematics
1 answer:
ipn [44]3 years ago
3 0
|\Omega|=C(23,6)=\dfrac{23!}{6!17!}=100947\\
|A|=C(17,6)=\dfrac{17!}{6!11!}=12376\\\\
P(A)=\dfrac{12376}{100947}=\dfrac{1768}{14421}
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