Answer:
Ans: -21.87 ≅ -22°C
Step-by-step explanation:
T(x)=-22+44e^-0.03x
Initial temperature (x = 0):
T(0) = = -22 + 44e-0.03(0) = -22 + 44(1) = 22°C
After 18 minutes (x = 18):
T(18) = -22 + 44e-0.03(18) = -21.87°C ≅ -22°C
Answer:
I think that5 it is the secend one
Step-by-step explanation:
376.99 try that the formula is 2x3.14x5x12
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
