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alisha [4.7K]
3 years ago
12

Function g can be thought of as a translated (shifted) version of f(x)=x^2.

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

g(x) = x² - 3

Step-by-step explanation:

A quadratic function has been given as,

f(x) = x²

If the function f is translated by 'h' unit down over the y-axis, the new function obtained by the translation is,

g(x) = x² - h

From the graph attached, h = 3 units (shift of 3 units downwards)

Therefore, g(x) = x² - 3 will be the translated version of f(x).

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The average temperature in the North Pole in the summer is 32 degrees F. The average temperature in the North Pole in the winter
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What is the value of m in the ecuation 1/2m -3/4n = 16, when n =8 ?
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2 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6
faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0
4 years ago
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