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TEA [102]
3 years ago
12

What additional information is needed to prove that the triangles are congruent using the AAS congruence theorem? LO ≅ LM OA ≅ M

A AngleLOA ≅ AngleLMA AngleLAO ≅ AngleLAM
Mathematics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

∠LOA≅∠LMA

Step-by-step explanation:

The first two options are incorrect because you need one more set of congruent ANGLES, not SIDES. The last option would prove congruency, but through ASA, not AAS. So it would be the third option.

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Hi- I need help please to get my HS diploma...did not graduate :(
andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

#SPJ1

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