Answer:
78%
Step-by-step explanation:
% increase = Increase ÷ Original Number × 100
% increase= 35.8/46 *100= 77.82=78 %
Answer:

A maximum of 112 number of 100 - kilograms can be loaded in the container.
Step-by-step explanation:
Given that:
Weight of each crate = 100 kg
The greatest weight that can be loaded in the container = 24000 kg
Weight already loaded in the container = 12800 kg
To find:
The inequality to determine the value
i.e. number of 100 - kilograms that can be loaded in the shipping container?
Solution:
Weight already loaded = 12800 kg
Let the number of 100 - kilograms that can be loaded in the container = 
Weight of
= 100
kg
This combined weight nor be greater than the capacity of the container.
OR we can say, it must be lesser than or equal to greatest weight that can be loaded into the container.


i.e. a maximum of <em>112</em> number of 100 - kilograms can be loaded in the container.
The pile contains 17 quarters and 15 half-dollars.
Let <em>x</em> = the number of quarters and <em>y</em> = the number of half-dollars.
We have two equations:
(1) $0.25<em>x</em> + $0.50<em>y</em> = $11.75
(2) <em>x</em> = <em>y</em> +2
Substitute the value of <em>x</em> from Equation (2) into Equation (1).
0.25(<em>y</em>+2) + 0.50<em>y</em> = 11.75
0.25<em>y</em> + 0.50 + 0.50<em>y</em> = 11.75
0.75<em>y</em> = 11.75 – 0.50 = 11.25
<em>y</em> = 11.25/0.75 = 15
Substitute the value of <em>y</em> in Equation (2).
<em>x</em> = 15 + 2 = 17
The pile contains 17 quarters and 15 half-dollars.
<em>Check</em>: 17×$0.25 + 15×$0.50 = $4.25 + $7.50 = $11.75.
Answer:
Step-by-step explanation:
Answer:
y > x - 3
Step-by-step explanation:
y - x > -3
This is an equation of a straight line graph.
Taking x to the right side, we get:
y > -3 + x
Rearranging, we get:
y > x - 3