<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer: Joey is faster
Step-by-step explanation: Because in 1 hour Joey is run 4 mile but in 1 hour Chandler is run 2 mile
The right answer is Option A.
Step-by-step explanation:
Let,
x be the postcards
y be the large envelops
According to given statement;
14x+5y=12 Eqn 1
10x+15y=24.80 Eqn 2
Multiplying Eqn 1 by 3;
Subtracting Eqn 2 from Eqn 3;
Dividing both sides by 32
Putting x=0.35 in Eqn 1;
Dividing both sides by 5
Therefore, one large envelope costs $1.42
The right answer is Option A.
Keywords: linear equations, subtraction
Learn more about linear equations at:
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The waitress earns $425 weekly.
Work:
Use proportions.
x 4
------- = ------
4,200 100
4,200 x 4 = 16800
100 multiply x = 100x
16800 divided by 100 = 168
Commission = $168
Base salary = $257
$168 + $257 = $425
Answer:
14
Step-by-step explanation:
3 + 2 + (5 - 1) + 5
Always solve the ones inside the parentheses first.
3 + 2 + (4) + 5
5 + 4 + 5
9 + 5
= 14
