Answer:
The one furthest to the right.
The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Answer:
5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Circumference C=2πr r=radius 
C=2(3.14)9.7
C=60.9
Answer:
- Decay rate, r = 0.014
- Initial Amount =120,000

- P(10)=104,220
Step-by-step explanation:
The exponential function for growth/decay is given as:

In this problem:
The city's initial population is 120,000 and it decreases by 1.4% per year.
- Since the population decreases, it is a Decay Problem.
- Decay rate, r=1.4% =0.014
- Initial Amount =120,000
Therefore, the function is:

When t=10 years
