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Katarina [22]
3 years ago
15

1. i will give you brainliest if ur right

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0

Answer:

the answer of this question is......

I think 134

but I can't explain that

I'm so sorry

:-/

ArbitrLikvidat [17]3 years ago
4 0

Answer:

141

Step-by-step explanation:

This is a seven-sided pentagon. We can find the total sum of all the angles in the pentagon first.

Sum of angles in a pentagon = (7-2) × 180

                                                = 5 × 180

                                                = 900

∠B = 900 - 148 - 90 - 142 - 130 - 129 - 120

     = 141

Remember:

Formula of sum of angles in pentagon = (n-2) × 180 where n is the number of sides the pentagon has. Hope this helps :)

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Answer:

The one furthest to the right.

3 0
3 years ago
The population of a certain town was 10,000 in 1990. The rate of change of the population, measured in people per year, is model
Katena32 [7]

The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

Solution :

According to the question,

The rate of change of population is given as :

$\frac{dP(t)}{dt}=200e^{0.02t}$  in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

                    $=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$

                   $=10,000[e^{0.4}-1]$

                    $=10,000[0.49]$

                    =4900

$\frac{dP(t)}{dt}=200e^{0.02t}$

$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

This is initial population.

k is change in population.

So in 1995,

$P=P_0e^{kt}$

   $=10,000e^{0.02(5)}$

   $=11051$

In 2000,

$P=10,000e^{0.02(10)}$

   =12,214

Therefore, the change in the population between 1995 and 2000 = 1,163.

8 0
3 years ago
Y = 2x + 1 its line intercept slope please answer quickly im in class rnnn
Serjik [45]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
The radius of a circle is 9.7 m. Find the circumference to the nearest tenth?(help its urgent)
yulyashka [42]

Answer:

Step-by-step explanation:

Circumference C=2πr  r=radius \pi =3.14

C=2(3.14)9.7

C=60.9

7 0
3 years ago
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
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