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3 years ago

#2. Use substitution to solve the system of equations

Mathematics

1 answer:

steposvetlana [31]3 years ago

5 0

Step-by-step explanation:

3(3y) -5y+12

6y-5y+12

Y+12

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Select each correct answer.

egoroff_w [7]

A) reflect graph over x-axis (minus in front)
e) compress the graph to the x-axis (coefficient 1/2)
f) translate the graph to the right (x-9), minus between x and 9.

3 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION!!!!!!

mr Goodwill [35]

From the table, y varies directly as x. Therefore, the constant of variation is k = 2 and y = 2x.

<h3>How to find a direct variation?</h3>

For direct variation,

y ∝ x

Therefore,

y = kx

where

k = constant of proportionality

Hence,

(-2, -4)

-4 = -2k

k = -4 / -2

k = 2

(-4, -8)

y = -4(2) = -8

Therefore,

k = 2 and y = 2x

learn more on variations here: brainly.com/question/2315806

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5 0

2 years ago

Given that x and y are real numbers find the possible values of x and y if (x+y)+(x-y)i=7+3i

atroni [7]

(x+y)+(x-y)i=7+3i

x+y =7

x-y =3

add these two equations together

x+y =7

x-y =3

------------------

2x = 10

divide by 2

x=5

x+y = 7

5+y =7

subtract 5 from each side

y =2

Answer: x=5

y=2

5 0

4 years ago

A bulb can either be on or off. A board contains connected to a randomization circuit that lights up a random sequence every tim

kari74 [83]

The question is incomplete. The complete question is :

A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence every time it is turned on. What is the probability that all the lights will switch on ?

Solution :

It is given that :

There is board connected to = 20 bulbs

And one can either be put ON or put OFF.

Therefore the chance that a bulb is ON = $\frac{1}{2}$