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Yuki888 [10]
4 years ago
11

A car can travel 234 miles on 26 gallons of gasoline. How far can it travel on 51 gallons?

Mathematics
2 answers:
castortr0y [4]4 years ago
7 0

Answer:

459 Miles

Step-by-step explanation:

fenix001 [56]4 years ago
5 0
If a car can travel 234 miles on 26 gallons, that means each gallon supplies 9 miles.
234/26=9
So, if a car has 51 gallons, it’ll be 51 x 9=459
The car can travel 459 miles on 51 gallons.
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Plz help ASAP please please ​
ss7ja [257]

Answer:

9030.75

Step-by-step explanation:

5039.16/.558=9030.752688

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9030.75

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3 0
4 years ago
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Math question is in the picture
IrinaVladis [17]

Answer:

s = -3, -7

Step-by-step explanation:

5 0
3 years ago
How to put 33 into 4:7
Tema [17]
4+7 = 11
so
33 / 11 = 3

4 x 3 = 12
7 x 3 = 21

so answer
4:7 = 12:21
4 0
3 years ago
Find all complex solutions of 2x^2-x+8=0
kumpel [21]

Answer:

x = 1 − √63i / 4 , x = 1 + √63i / 4

Step-by-step explanation:

Let's use the formula −b±√b2−(4ac) / 2⋅a

=  ax^2+bx+c=0

= 2x^2-x+8=0

Let's substitute 2 for a, −1 for b, and 8 for c in the formula of quadratic equation.

x = −1±√−12−(4⋅2⋅8) / 2⋅2

x = 1±√1−64 / 4

x = 1±√−63 / 4

x = 1±√63⋅−1 / 4

x = 1±√63√−1 / 4

x = {1−√63i / 4 , 1±√63i / 4}

7 0
3 years ago
A standard number cube numbered one through six on each side is rolled five times. What is the probability of landing on a three
Sav [38]

Answer:

  • 1/243 ≈ 0.004 (which is a low probability)

Explanation:

The event landing on a three or four on a rolling is independent of the event  of landing on a three or four on any other rolling.

Thus, for independent events you calculate the joint probability as the product of the probabilities of each event:

  • P(A and B and C and D and E) = P(A) × P(B) × P(C) × P(D) × P(E)

Here, P(A) = P(B) = P(C) = P(D) = P(E) = probability of landing on a three or four.

Now to calculate the probability of landing on a three or four, you follow this reasoning:

  • Positive outcomes = three or four
  • Number of positive outcomes = 2
  • Possible outcomes = one, two, three, four, five, or six
  • Number of possible outcomes = 6
  • Probability = numer of positive outcomes / numer of possible outcomes
  • Probability = 2/6 = 1/3

Finally, probability of landing on a three or four on all five rolls: (1/3)⁵ = 1/243 ≈ 0.004 ← answer

5 0
4 years ago
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