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Yuki888 [10]
3 years ago
11

A car can travel 234 miles on 26 gallons of gasoline. How far can it travel on 51 gallons?

Mathematics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

459 Miles

Step-by-step explanation:

fenix001 [56]3 years ago
5 0
If a car can travel 234 miles on 26 gallons, that means each gallon supplies 9 miles.
234/26=9
So, if a car has 51 gallons, it’ll be 51 x 9=459
The car can travel 459 miles on 51 gallons.
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Help please due in a hour
beks73 [17]

Answer:

The answer is equal to 3/10

Step-by-step explanation:

The values are not very clear

If it's the product of 3/3 and 3/10

Then 3/3 x 3/10

= 9/30

= 3/10

4 0
3 years ago
Henry took his daughter and some friends to the fair.he bought 1 adult ticket for $11, and, n, child tickets for 10 each. He spe
Flura [38]

Answer: 1+$11=$12

$12 +$51= $75 tickets that Henry bought

5 0
3 years ago
Read 2 more answers
Which of the following statements is true?
wolverine [178]

Answer:

D: Point E is the midpoint of segment AC

Step-by-step explanation:

The midpoint is a point where it is in the middle of a line, line segment, or ray.

Congruent means something that is exactly the same.

Congruent triangles are two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.

Bisect means separating something into two precise and equal pieces/ angles.

Similar triangles means two objects are similar if they have the same shape, or one has the same shape as the mirror image of the other.

8 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
You need to purchase rolls of sod grass for a client's lawn, which is 75 feet by 100 feet. The large rolls of sod grass are 116
Nikolay [14]

The number of sod grasses needed is about one and half for the clients lawn

1 1/2 sod grasses

<h3> Area of Rectangle</h3>

Given Data

  • Size of clients Lawn
  • Length = 75 feet
  • Width = 100 feet

Area of client's Lawn = Length * Width

= 75*100

= 7500 square feet

Size of large rolls of sod grass

  • Length = 116 feet
  • Width = 42 feet

Area of large rolls of sod grass  = Length * Width

= 116*42

= 4872 square feet

The number of sod grass needed

= 7500/4872

= 1.53

Learn more about rectangles here

brainly.com/question/25292087

4 0
2 years ago
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