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3 years ago

A car can travel 234 miles on 26 gallons of gasoline. How far can it travel on 51 gallons?

Mathematics

2 answers:

castortr0y [4]3 years ago

7 0

Answer:

459 Miles

Step-by-step explanation:

fenix001 [56]3 years ago

5 0

If a car can travel 234 miles on 26 gallons, that means each gallon supplies 9 miles.
234/26=9
So, if a car has 51 gallons, it’ll be 51 x 9=459
The car can travel 459 miles on 51 gallons.

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If m<ECD is six less than five times m<BCE. and m<BCD = 162°, find each measure.(Sorry bout using the wrong signs, but

tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

then subtract six from this product the answer will be the measure

of angle ECD

∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

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Answers to 5 and 6 please need help please!

Tresset [83]

My friend says 5 is 60 and 6 is b.

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Montano1993 [528]

Answer:

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Step-by-step explanation:

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HELP NEEDED ASAP!! Amani computed in a two-way table the relative frequencies of sales of homes listed with two different real e

guajiro [1.7K]

The answer is c.

When you look at the data, in the first column, the frequency of sales of both are similar. Even the second column shows similar data. Association is determined if there is a significant difference between the data in each column/row depending on what you are aiming to answer.

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The height, h, in feet of a ball above the ground is given by h = −16t2 + 64t + 80, where t is the time in seconds. How long doe

Gwar [14]

Answer:

t = 5 seconds

Step-by-step explanation:

It is given that, the height h, in feet of a ball above the ground is given by :

$h=-16t^2+64t+80$

Where t is in seconds

We need to find how long does it take the ball to hit the ground? When it hits the ground, its height will be equal to 0. So,

$-16t^2+64t+80=0\\\\t=\dfrac{-64\pm \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=\dfrac{-64+ \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16},\dfrac{-64-\sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=-1\ s\ \text{and}\ t=5\ s$

Neglecting negative time.

It means ball will take 5 seconds to hit the ground.

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