3 years ago

Find the area of a traingle given that the base is 19.5cm and height is 8 4/5cm.

Mathematics

1 answer:

Phoenix [80]3 years ago

3 0

Answer:

85.6cm

Step-by-step explanation:

Area of a triangle =1/2*b*h

Where base=19.5cm while the height is 8 4/5 = 8.8

Area = 1/2 * 19.5cm * 8.8cm

Area = 171.6cm/2

Area=85.6cm

You might be interested in

PLEASE HELP!! GRADE 7 MATHEMATICS!!!

Rzqust [24]

The area of 3x5 face is used 4 times rather then twice
S=94in ^2

5 0

3 years ago

Good evening, I am taking an Algebra class for the first time after 50 years, and can not remember how to find the point-slope f

Olin [163]

m=-1/5p x 10.4
m=-1/5p x 52/5
m=-52/25p

8 0

3 years ago

Fiona is pricing two bicycles one is 175 with 10% and the other is 225 with 35% off which bicycle can she afford if she has 150

Gekata [30.6K]

If the one for $175 is 10% off, that means Fiana pays 90% of the price

175 * 0.9 = $157.50

It is too expensive because 157.50 is more than the 150 Fiana has.

The second bike for $225 is 35% off which means Fiana pays 65% of the price.

225 * 0.65 = $146.25

She CAN afford the bike for $225

5 0

3 years ago

Read 2 more answers

Work out the percentage change when a price of £80 is increased to £100.

Mars2501 [29]

Answer:

125%

Step-by-step explanation:

80/100=8

80*x=100

100/80=1.25

1.25*100=125

x=125%

3 0

3 years ago

What are the dimensions of a rectangular box with a volume of 50b 3 + 75b2 - 2b - 3?

Inessa [10]

Answer:

$\large\boxed{(2b+3)\times(5b-1)\times(5b+1)}$

Step-by-step explanation:

The formula of a volume of a rectangular box:

$V=lwh$

l - lenght

w - width

h - height

$V=50b^3+75b^2-2b-3=25b^2(2b+3)-1(2b+3)\\\\=(2b+3)(25b^2-1)=(2b+3)(5^2b^2-1^2)\\\\=(2b+3)\bigg((5b)^2-1^2\bigg)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(2b+3)(5b-1)(5b+1)$

Therefore the dinemsions of thisp prism are:

$(2b+3)\times(5b-1)\times(5b+1)$

5 0

2 years ago

Read 2 more answers