3 years ago

Find the area of a traingle given that the base is 19.5cm and height is 8 4/5cm.

Mathematics

1 answer:

Phoenix [80]3 years ago

3 0

Answer:

85.6cm

Step-by-step explanation:

Area of a triangle =1/2*b*h

Where base=19.5cm while the height is 8 4/5 = 8.8

Area = 1/2 * 19.5cm * 8.8cm

Area = 171.6cm/2

Area=85.6cm

You might be interested in

2. Find the area; reduce to lowest terms:<br> Length: 2 3/4 feet width 2/5 feet

Lelu [443]

Answer:

1 2/20

Step-by-step explanation:

7 0

3 years ago

Find ration aqual to the radio given 12:7

Veronika [31]

12:7*2=24:14

The radio is of 12:7 is 14:14

3 0

3 years ago

Pleaseeeee help 50 points + brainliest mark

natka813 [3]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

This model is composed of two shapes. What is the area of this figure?

mote1985 [20]

Measurements of 30 I believe yw

7 0

3 years ago

Read 2 more answers

Prove that 1+cosA/sinA + sinA/1+cosA=2cosecA

Alla [95]

$\frac{1+cos\alpha}{sin\alpha}+\frac{sin\alpha}{1+cos\alpha}=2cosec\alpha\\\\L=\frac{(1+cos\alpha)(1+cos\alpha)+sin\alpha\cdot sin\alpha}{sin\alpha(1+cos\alpha)}=\frac{1+2cos\alpha+cos^2\alpha+sin^2\alpha}{sin\alpha(1+cos\alpha)}\\\\=\frac{1+2cos\alpha+1}{sin\alpha(1+cos\alpha)}=\frac{2+2cos\alpha}{sin\alpha(1+cos\alpha)}=\frac{2(1+cos\alpha)}{sin\alpha(1+cos\alpha)}\\\\=\frac{2}{sin\alpha}=2\cdot\frac{1}{sin\alpha}=2cosec\alpha=R$

5 0

3 years ago