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Oxana [17]
3 years ago
7

¿A cuantos milesimos equivale 1.2 centesimos?​

Mathematics
1 answer:
Doss [256]3 years ago
8 0

Answer:

Dbnknak wjsbsks n kshs wka a whs

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I have 3 Sisters each<br>Sister has 3 sisters. How<br>many of us are there?​
fgiga [73]

Answer:

4 sisters

Step-by-step explanation:

-This is a logic question.

-Given that she has 3 sisters, it only means that the 4 are siblings of the same family.

-As such, eaxh sister can correctly claim to have 3 sisters.

Hence, there is a total of 4 sisters.

7 0
3 years ago
Find the magnitude of wy for W( 3. - 3, 1) and X(8. –3,-6)
Mashutka [201]

Answer:

√74

Step-by-step explanation:

there is no y.

wx=<8-3,-3+3,-6-1>=<5,0,-7>

|wx|=√(5²+0²+(-7)²)=√(25+49)=√74

8 0
3 years ago
At the thrift store the ratio of long sleeves shirts to short sleeve shirts was 4:3 for every short sleeve shirts how many long
AlexFokin [52]
Does it say how many shirts there are total?
5 0
3 years ago
Read 2 more answers
Jeanie's car averages 35 miles per gallon and the current cost of gasoline is $2.56 per gallon. To the nearest cent, what is the
MA_775_DIABLO [31]
If she can go 35 miles with 1 gallon, and 1 gallon costs $2.56, all you need to do is divide $2.56 by 35 to get the cost per gallon. 
3 0
3 years ago
Read 2 more answers
The number of contaminating particles on a silicon wafer prior to a certain rinsing process was determined for each wafer in a s
Allushta [10]

Answer:

a) P(X\geq 1) = 1-P(X

b) P(X\geq 5) = 1-P(X

And replacing we got:

P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71

Step-by-step explanation:

For this case we can solve this problem creating the following table

Number of particles      Frequency         Rel. Frequency

             0                            1                       1/100 =0.01

             1                             2                      2/100 =0.02

             2                            3                       3/100=0.03

             3                            12                     12/100=0.12    

             4                            11                       11/100=0.11

             5                            15                      15/100=0.15

             6                            18                      18/100=0.18

             7                            10                       10/100=0.1

             8                            12                       12/100=0.12

             9                            4                         4/100=0.04

             10                           5                         5/100=0.05

             11                            3                         3/100=0.03

             12                           1                          1/100=0.01

             13                           2                         2/100=0.02

             14                           1                          1/100=0.01

           Total                       100                            1

We assume on this case the the relative frequency represent the probability.

Let X the number of contaminating particles on a silicon wafer

What proportion of the sampled wafers had at least one particle?

For this case we can use the complement rule like this:

P(X\geq 1) = 1-P(X

At least five particles?

Again for this case we can use the complement rule and we got:

P(X\geq 5) = 1-P(X

And replacing we got:

P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71

5 0
3 years ago
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