The force that one surface exerts on another when the two rub against each other is called

is it true or false that all atom´s electrons can interact with the electrons of other atom to form bonds

Sveta_85 [38]

False. only valence electrons can bond with other atoms' electrons.

3 0

3 years ago

Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.

denpristay [2]

Answer:

For a: The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b: The mass of methane gas produced will be 10.384 g.

Explanation:

For the given chemical reaction:

$2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ$

For a:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

$\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol$

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = $\frac{252.8}{2}\times 0.749=94.6736kJ$

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b:

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = $\frac{2}{252.8}\times 82.1=0.649mol$ of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

$0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g$

Hence, the mass of methane gas produced will be 10.384 g.

7 0

3 years ago

Geology belongs to which main category of science?

e-lub [12.9K]

Geology belongs to the Earth Science category I believe.

5 0

3 years ago

Read 2 more answers

HELP ASAP!!! 2C4H10(g) + 1302 ===> 8CO2(g) + 10H2O(g)

Ivan

Answer:

30.34g (corrected to 4 significant figures).

Explanation:

Take the atomic mass of C=12.0, H=1.0, O=16.0.

no. of moles = mass / molar mass

So, no. of moles of butane reacted = 10 / (12x4 + 1x10)

= 0.172414 mol

Since O2 is in excess and butane is the limiting reagent, the no. of moles of carbon dioxide produced depends on the no. of moles of butane reacted.

From the equation, the mole ratio of butane:Carbon dioxide = 2: 8 = 1: 4,

meaning 1 mole of butane gives 4 moles of CO2.

Using this ratio,

we can deduce that the no. of moles of CO2 produced = 0.172414 x 4

=0.689655 mol

As mass = no. of moles x molar mass

mass of CO2 produced = 0.689655 x (12.0+16.0x2)

=30.34g (corrected to 4 significant figures).

6 0

3 years ago

insert the missing coefficients in the following partially balanced chemical equations S+6HNO=HSO4+NO+H2O

lianna [129]

Answer:

S + 6HNO₃ ⟶ H₂SO₄ + 6NO₂ + 2H₂O

Step-by-step explanation:

S + 6HNO₃ ⟶ H₂SO₄ + NO₂ + H₂O

One way is to balance this equation is the oxidation number method.

Step 1. Calculate the oxidation number of every atom:

S⁰ + H⁺¹N⁺⁵O₃⁻² ⟶ H₂⁺¹S⁺⁶O₄⁻² + N⁺⁴O₂⁻² + H₂⁺¹O⁻²

Step 2. Identify the changes in oxidation number:

S: +0 ⟶ +6; Change = +6

N: +5 ⟶ +4; Change = -1

Step 3. Equalize the changes in oxidation number.

You need 6 atoms of N for every 1 atom of S. This gives us total changes of -6 and + 6.

Step 4. Insert coefficients to get these numbers.

1S + 6HNO₃ ⟶ 1H₂SO₄ + 6NO₂ + H₂O

Step 5. Balance O.

We have fixed 18 O on the left and 16 O on the right. We need 2 more O on the right. Put a 2 in front of H₂O.

1S + 6HNO₃ ⟶ 1H₂SO₄ + 6NO₂ + 2H₂O

Every formula now has a coefficient. The equation should be balanced.

Step 6. Check that all atoms balance.

Atom Left-hand side Right-hand side

S 1 1

H 6 6

N 6 6

O 18 18

The balanced equation is

S + 6HNO₃ ⟶ H₂SO₄ + 6NO₂ + 2H₂O

5 0

3 years ago

The force that one surface exerts on another when the two rub against each other is called _