I need help with the evens in that picture
1 answer:
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Answer:
To find the surface area of this pyramid, we must find the <u>area</u> of one <u>triangle</u> flap which we then <u>multiply by 4</u> because there are 4 of those equal triangle flaps surrounding the base(square). Once we find the area of those triangles, we then find the <u>base(square)'s area</u>. Next, we add all those areas together to get the result of the surface area.
Formula for area of triangle;
A = BH x 1/2
Where 'B' represents the base, 'H' represents the height, and 1/2 is just dividing the product of those two lengths by 2.
Plug in what you know, given that the base of one triangle is 4, and the height is 6.
A = 4(6) x 1/2
A = 24 x 1/2
A = 24/2
A = 12, the area of <em>one triangle is 12 inches</em>.
Now, we find the area of all the triangles by multiplying the area of one triangle by 4.
12 = Area of triangle
4 triangles in total, so:
12(4)
= <u>48 inches</u> is the <u>area</u> of <u>all the triangles</u>.
Now we find the area of the base(square) using the formula;
(vol of square formula)
A =
Where 's' represents one side of the square which is being squared.
or
A = l · w
Where 'l' represents the length and 'w' represents the width.
Plug in what you know, given that one side of the square is 4 inches (as well as the length and width).
(I'll be using the formula )
A =
A = 4^2 ← (The symbol ' ^ ' means raised to the power of.)
A = 16, the <u>area</u> of the <u>base(square)</u> is <u>16 inches</u>.
Now we add both areas together:-
48 + 16
= <u>64 inches^2</u> is the surface area, your answer is A.