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ser-zykov [4K]
3 years ago
8

I need help with the evens in that picture

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

i would help you but i cannot see the image.

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What is the value of x in the equation
chubhunter [2.5K]

Well I solved it and This is what i got

3 0
3 years ago
A grocer bought n eggs at $x each. He marked up the price of each egg by $y and sold all of them. Find the sales amount, express
Alex777 [14]

Answer:

Sales = n \times ($x + $y)

Step-by-step explanation:

The basic simple sales equation is

Quantity \times Price = Sales

Here in the given question,

Total quantity of sales = n

Price = Cost + markup

(Markup refers to the profit added to cost)

Thus price = $x (cost) + $y (markup)

Sales = n \times ($x + $y)

Sales amount is the total amount received from sales of products, total quantity at some price provided.

4 0
3 years ago
SOMEONE PLEASEEEEE HELP .... GIVING BRAINILEST!!!
Vanyuwa [196]

Answer: Value of M: -49

Value of N: 24

Step-by-step explanation:

Yw and pls mark me brainiest

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2 years ago
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Identify the slope and y-intercept of the given graph.
Kryger [21]
The y intercept is 4
4 0
3 years ago
a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the
nlexa [21]

Answer:

The standard equation of the parabola is:

y=-\frac{3}{2}x^2+12x-18

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}

Then the equation of the parabola becomes:

y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18

7 0
3 years ago
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