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katen-ka-za [31]
3 years ago
14

if you deposit $15 a week into the savings account what is the minimum number of weeks it will take for you to be able to open a

checking account with at least $200 and still have $25 in your savings account?
Mathematics
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

15 weeks

15 times 15 is 225

$200 (checking) $25 (savings)

:)

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Decide whether each equation is true for all, one, or no values of x.
Gala2k [10]

Answer:

<u>b) true for one value of x</u>

<u>a) true for all values of x</u>

<u>c) true for no values of x</u>

sorry if they are wrong

Step-by-step explanation:

2x + 8 = -3.5x + 19

a) true for all values of x

<u>b) true for one value of x</u>

<u></u>

c) true for no values of x

9(x - 2) = 7x + 5

<u>a) true for all values of x</u>

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b) true for one value of x

c) true for no values of x

3(3x + 2) - 2x = 7x + 6

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3 0
3 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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antoniya [11.8K]
6(-3)*4(3)*3
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Answer: -432
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4 years ago
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natima [27]

Answer:

$12

Step-by-step explanation:

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