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Oksanka [162]
3 years ago
12

The simplest form of 4√576 is ?

Mathematics
2 answers:
N76 [4]3 years ago
8 0

Answer:

96 or √144

Step-by-step explanation:

Divide 576 by 4 to get 144. There will be no values outside of the square root sign because 4 goes directly into 576 with no remainders.

k0ka [10]3 years ago
3 0

Answer:

Step-by-step explanation:

Factorize 576

4\sqrt{576}=4\sqrt{3*3*2*2*2*2*2*2}\\\\ =4*3*2*2*2\\\\=96\\

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Doug digs a hole that is 1.7 feet below ground level. He plants a bush that is 3 2/10 feet tall from the bottom of the root to t
ioda
1.7 = 1 7/10 = 17/10
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5 0
3 years ago
A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?
DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals 2.20\times 10^{8}\,Pa. The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress (\sigma), measured in pascals, in the wire with circular cross-section is:

\sigma = \frac{4\cdot F}{\pi\cdot D^{2}} (1)

Where:

F - Axial force, measured in newtons.

D - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that F = 800\,N and D = 0.002\,m, then the axial stress experimented by the titanium wire is:

\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}

\sigma \approx 2.546\times 10^{8}\,Pa

Since stress is greater than ultimate strength, the wire will break.

3 0
2 years ago
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stiv31 [10]

Answer:

A

Step-by-step explanation:

Hello There!

The y value of ABC was subtracted by 7 to get to the figure A'B'C'

So the rule for the given transformation would be

(x,y) ---> (x,y-7)

5 0
3 years ago
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ikadub [295]

Answer:

9. It seems he was inactive/taking a break, as the line is completely straight.

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Step-by-step explanation:

4 0
2 years ago
Find the volume of the solid formed by rotating the region bounded by the given curves about the indicated axis. Y = 1x, y = 1,
Goryan [66]

The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.

Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is

π (radius) (height) = π (1/y)² ∆y = π/y² ∆y

and the volume of a stack of n such disks is

\displaystyle V_n = \sum_{i=1}^n \pi {y_i}^2 \Delta y

where y_i is a point sampled from the interval [1, 5].

As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,

\displaystyle V = \lim_{n\to\infty} V_n = \int_1^5 \frac{\pi}{y^2} \, dy

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8 0
2 years ago
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