2(-3y-1)+(2y+7) I need to know how to solve this equation
1 answer:
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Answer:
The lengths of the bases are 9 inches and 15 inches.
Step-by-step explanation:
The area of trapezoid is
Given that the height of a trapezoid is 8 in. and its area is 96 in².
Assume the bases of the trapezoid be b₁ and b₂.
Since one base of the trapezoid 6 in. longer than the other.
Let, b₁=b₂+6
The area of the trapezoid is
in²
in²
in²
According to the problem,
[ Multiplying
]
Then,
=9+6
=15 in
The lengths of the bases are 9 inches and 15 inches.
Answer:
0.7325 to 5.6675 ug/dl
Step-by-step explanation:
The middle 90% will be 45% above the mean and 45% below the mean. This means
0.5-0.45 = 0.05 and
0.5+0.45 = 0.95
We use a z table. Look in the cells; find the values as close to 0.05 and 0.95 as we can get.
For 0.05, we have 0.0505 and 0.0495; since these are equidistant from 0.05, we use the value between them. 0.0505 is z=-1.64 and 0.0495 is z=1.65; this gives us z=-1.645.
For 0.95, we have 0.9495 and 0.9505; since these are equidistant from 0.95, we use the value between them. 0.9495 is z = 1.64 and 0.9505 is z=1.65; this gives us z = 1.645.
Now we use our z score formula,
Our two z scores are 1.645 and -1.645; our mean, μ, is 3.2; and our standard deviation, σ, is 1.5:
Multiply both sides by 1.5:
Add 3.2 to each side:
2.4675+3.2 = X-3.2+3.2
5.6675 = X
Multiply both sides by 1.5:
Add 3.2 to each side:
-2.4675+3.2 = X-3.2+3.2
0.7325 = X
Our range is from 0.7325 to 5.6675.