The half life of the substance is 6.92 days.
<h3>What is the Half life ?</h3>
Half life can be defined as the time required to reduce the concentration to half of its initial value.
Here the equation given is
The concentration will reduce to half therefore
so,
ln 0.5 = - 0.1001 * t(1/2)
-0.693 = -.1001 * t(1/2)
t(1/2) = 6.92 days.
Therefore the half life of the substance is 6.92 days.
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V=(4/3)pir^2
c=2pir
12=2pir
divide 2
6=pir
divide by pi
6/pi=r
sub for r
V=(4/3)pi(6/pi)^2
V=(4/3)pi(36/(pi^2))
V=(4/3)(36/pi)
V=144/(3pi)
V=48/pi
aprox pi=3.141592
V=15.2788777155
V=15.28 in^3
Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
Answer:
d
Step-by-step explanation:
Rewrite in slope intercept form (move 5x to the right, divide both sides by 2, and reorder the terms)
Step-by-step explanation:
this is your answer.........
