Answer:
V = 3.97 m/s
Explanation:
Mass of a man, M = 85 kg
Mass of a bullet, m = 8 g = 0.008 kg
Speed of bullet, v = 410 m/s
We need to find the speed of a man in order to have the same kinetic energy as that of the bullet. Let the kinetic energy of the bullet is k. So,
Since, k = K (K is the kinetic energy of the man and Let V is the speed)
So, the speed of the man is 3.97 m/s.
<h2>
Stopping force on the bullet is 1073.23 N to the left.</h2>
Explanation:
Mass of bullet, m = 11.0 g = 0.011 kg
Initial speed of bullet, u = 210 m/s
Final speed of bullet, v = 0 m/s
Displacement of bullet, s = 22.6 cm = 0.226 m
We have equation of motion v² = u² + 2as
Substituting
0² = 210² + 2 x a x 0.226
a = -97566.37 m/s²
We have
Force, F = Mass x Acceleration
F = 0.011 x -97566.37 = -1073.23 N
Negative means opposite to the direction of motion of bullet.
Stopping force on the bullet is 1073.23 N to the left.
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