Se necesita 105 j de trabajo para mover 2,7 c de carga de la placa negativa a la placa positiva de un condensador de placa paralela. Qué diferencia de tensión existe entre las placas
Answer:
150 Nm
Explanation:
Unit conversion:
5 cm = 0.05 m
8 cm = 0.08 m
The torque generated by such force would be the product of the force by the muscles and the moment arm of that force.
T = FR
Where T is the torque (Nm), F = 3000 N is the force and R = 0.05 m is the moment arm
T = 3000*0.05 = 150 Nm
Answer:
a) 10.6V
b) E = 4.9V/m, +x direction
c) E = 4.9V/m, +x direction
Explanation:
You have the following function:
(1)
for the potential in a region between x=0 and x=6.00 m
a = 10.6 V
b = -4.90V/m
a) for x=0 you obtain for V:
b) The relation between the potential difference and the electric field can be written as:
(2)
the direction is +x
c) The electric field is the same for any value of x between x=0 and x=6m.
Hence,
E = 4.9V/m, +x direction
1) A The 78g
2) C Push on the wagon in the opposite direction as Jack with a force that is the same as Jack is applying.
