The set of all possible events Ω
Ω = 24 ( 4*7 = 28 stick)
<span>set of events favorable A
A = 7 ( </span><span>sticks of green is 7)
</span><span>Probability P
P(A) = A/</span>Ω = 7/28 = 1/4 = 0,25
Answer A
<span>The first person has the ability to draw seven green sticks of twenty-four </span>
Answer:
Step-by-step explanation:
∩ 
is asking for the intersection of sets 
and , or simply, which numbers can be found in both sets.
The numbers shared between the two sets are 
.
Next, we need to union this result with the set 
, or simply, combine the numbers in both sets together.
This would result in 
4x = student tickets, 7x = adult tickets
4(120) + 7x = 1500
480 + 7x = 1500
7x = 1020
X = 145 adult tickets
All you need to do is plug -5 into the second equation and you see it is near (-5, -8). When plugged into the top, you get (-5, -27/4) which comes out to ABOUT -6.75 for the Y value. The closest is actually a tie. The first option is .8 from the first and .45 from the second leading in a total distance of 1.25. The second, which is the fellow answer, is 1.2 from the first and .05 from the second, leading to 1.25 away.
The third, which is next closest is 1.8 from the first and .55 from the second leading to a distance of over 2 from the optimal, so only the first two are answers.
