The slope of the line that contains the point (13,-2) and (3,-2) is 0
<em><u>Solution:</u></em>
Given that we have to find the slope of the line
The line contains the point (13,-2) and (3,-2)
<em><u>The slope of line is given as:</u></em>

Where, "m" is the slope of line
Here given points are (13,-2) and (3,-2)

<em><u>Substituting the values in formula, we get,</u></em>

Thus the slope of line is 0
3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k
for this to be divisible by x every term must include x or get eliminated
the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3
so A) -3 is the solution
Answer:
+89
Step-by-step explanation:
Answer:
m=2/3.
Step-by-step explanation:
the equation for slope is y=mx+b, where m is slope. So, 2/3 is your slope.
Answer: I’m pretty sure it’s 3/4
Step-by-step explanation: you just count the difference of the x and y and then put the change of y over the change of x and that’s the slope. Also known as the m in y=mx+b