sandra cut her sandwich into 3 equal parts. she ate 1 part for lunch. what fraction of the sandwich did sandra eat for lunch?

A slitter assembly contains 48 blades. Five blades are selected at random and evaluated each day of sharpness. If any dull blade

Alex73 [517]

Answer:

Part a

The probability that assembly is replaced the first day is 0.7069.

Part b

The probability that assembly is replaced no replaced until the third day of evaluation is 0.0607.

Part c

The probability that the assembly is not replaced until the third day of evaluation is 0.2811.

Step-by-step explanation:

Hypergeometric Distribution: A random variable x that represents number of success of the n trails without replacement and M represents number of success of the N trails without replacement is termed as the hypergeometric distribution. Moreover, it consists of fixed number of trails and also the two possible outcomes for each trail.

It occurs when there is finite population and samples are taken without replacement.

The probability distribution of the hyper geometric is,

$P(x,N,n,M)=\frac{(\limits^M_x)(\imits^{N-M}_{n-x})}{(\limits^N_n)}$

Here x is the success in the sample of n trails, N represents the total population, n represents the random sample from the total population and M represents the success in the population.

Probability that at least one of the trail is succeed is,

$P(x\geq1)=1-P(x$

(a)

Compute the probability that the assembly is replaced the first day.

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48.

Number of blades selected at random from the assembly n= 5

Number of blades in an assembly dull is M = 10.

The probability mass function is,

$P(X=x)=\frac{[\limits^M_x][\limits^{N-M}_{n-x}]}{[\limits^N_n]};x=0,1,2,...,n\\\\=\frac{[\limits^{10}_x][\limits^{48-10}_{5-x}]}{[\limits^{48}_5]}$

The probability that assembly is replaced the first day means the probability that at least one blade is dull is,

$P(x\geq 1)=1- P(x$

(b)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48

Number of blades selected at random from the assembly N = 5

Number of blades in an assembly dull is M = 10

From the information,

The probability that assembly is replaced (P) is 0.7069.

The probability that assembly is not replaced is (Q) is,

$q=1-p\\= 1-0.7069= 0.2931$

The geometric probability mass function is,

$P(X = x)= q^{x-1} p; x =1,2,....=(0.2931)^{x-1}(0.7069)$

The probability that assembly is replaced no replaced until the third day of evaluation is,

$P(X = 3)=(0.2931)^{3-1}(0.7069)\\=(0.2931)^2(0.7069)= 0.0607$

(c)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48

Number of blades selected at random from the assembly n = 5

Suppose that on the first day of the evaluation two of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M = 2.

$P(x=0)=\frac{(\limits^2_0)(\limits^{48-2}_{5-0})}{\limits^{48}_5}\\\\=\frac{(\limits^{46}_5)}{(\limits^{48}_5)}\\\\= 0.8005$

Suppose that on the second day of the evaluation six of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M = 6.

$P(x=0)=\frac{(\limits^6_0)(\limits^{48-6}_{5-0})}{(\limits^{48}_5)}\\\\=\frac{(\limits^{42}_5}{(\limits^{48}_5)}\\\\= 0.4968$

Suppose that on the third day of the evaluation ten of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M

= 10.

$P(x\geq 1)=1- P(x$

The probability that the assembly is not replaced until the third day of evaluation is,

P(The assembly is not replaced until the third day)=P(The assembly is not replaced first day) x P(The assembly is not replaced second day) x P(The assembly is replaced third day)

=(0.8005)(0.4968)(0.7069)= 0.2811

5 0

4 years ago

Given the rectangle ABCD, AB has a slope of 2/3, what is the slope of BC?

erastova [34]

Answer:

slope = - $\frac{3}{2}$

Step-by-step explanation:

note that BC is perpendicular to AB, hence the slope of BC is the negative reciprocal of the slope of AB

$m_{BC}$ = - $\frac{1}{2/3}$ = - $\frac{3}{2}$

7 0

4 years ago

HI PLZ HELPI NEED AN ANSWER!! (And will mark brainliest if a legit answer thanks)

trapecia [35]

Option 3: a 90 degree rotation clockwise

You can tell that it is 90 degrees because the original started completely in quadrant 2 and the final image is completely in quadrant 1. If it was only rotated 45 degrees the final image would be part in quadrant 2 and part in quadrant 1. It was rotated clockwise because that is the way a clock goes.

Hope this helps! ;)

6 0

3 years ago

A bicycle store costs $4200 per month to operate. The store pays an average of $75 per bike. The average selling price of each

Lelechka [254]

Store should sell about 31 bicycle for average price of $135 each bicycle.

Step-by-step explanation:

To find bike we need Algebra to solve the equation.
when x = 1 , Y = 135 *x
When x 2 , Y = 135 *2
Formula you could apply to go for break even y = 135*x
Bicycle store pays about $4200
Algebra used for every business and working to make easy task.
It takes about 31 bicycle a month to get into break even.
Every store needs break even to not incur lost.
Break even point is equilibrium between income and expenses.

7 0

3 years ago

What are the measures of anglss a, b, and c? Show your work and explain your answers.

alexgriva [62]

A is 40

B is 50

C is 115

Explanation, A is the same as the opposite, A + B + 90 = 180, and C + 65 = 180

4 0

3 years ago