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TiliK225 [7]
3 years ago
11

Х+6y = 1 2х - Зу = 32

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

x = 13

y = (-2)

Step-by-step explanation:

<h2><u>Substitution Method</u><u>:</u></h2>

х + 6y = 1 and 2х - Зу = 32 are given equations

<u>Step 1:</u>

Name the equation

х + 6y = 1 ...(1)

2х - Зу = 32 ...(2)

<u>Step 2:</u>

From equation (1) we get,

x + 6y = 1

x = 1 - 6y

<u>Step 3:</u>

Put the Value of <u>x = 1 - 6y </u>in equation (2) we get,

2(1 - 6y) - Зу = 32

2 - 12y - 3y = 32

2 - 15y = 32

15y - 2 = - 32

15y = 2 - 32

15y = - 30

y = - 30/15

<em><u>y = - 2</u></em>

<u>Step 4:</u>

Then, put the value of <u>y = - 2</u><u> </u>in equation (1)

x + 6y = 1

x + 6(-2) = 1

x - 12 = 1

x = 12 + 1

<em><u>x = 13</u></em>

Thus, The value of x is 13 and y is (-2)

<h2><em>Verification:</em></h2>

13 + 6(-2) = 1 i.e., <em><u>13 - 12 = 1</u></em>

2(13) - З(-2) = 32 i.e., <em><u>26 + 6 = 32 </u></em>

vivado [14]3 years ago
6 0

Answer:

x+6y=12x-3y=32

Step-by-step explanation:

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