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damaskus [11]
2 years ago
15

Determine the radius and center of the circle with the following equation x^2+y^2-12x+24y-10=6

Mathematics
1 answer:
PolarNik [594]2 years ago
8 0

Answer:

Center: (6, -12)

Radius: 4

Step-by-step explanation:

<u>Complete the squares</u>

<u />x^2+y^2-12x+24y-10=6\\\\x^2-12x-10+y^2+24y=6\\\\x^2-12x-10+46+y^2+24y+144=6+46+144\\\\(x^2-12x+36)+(y^2+24y+144)=196\\\\(x-6)^2+(y+12)^2=196

Comparing with the standard form equation (x-h)^2+(y-k)^2=r^2, since r^2=196, then the radius of the circle is r=14. Also, the center of the circle would be (h,k)\rightarrow(6,-12).

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