Answer: (3x−2)(4x−1)
Step-by-step explanation:
<em>Start factoring with -11x.</em>
12x^(2)-11x+2
12x2+(−8−3)x+2
12x2+(−8x−3x)+2
12x2−8x−3x+2
<em>Factor the highest common denominator of each group.</em>
<em>Group the first two terms and the last two.</em>
(12x2−8x)+(−3x+2)
<em>Factor the highest common denominator (MCD) of each group.</em>
<em>4x(3x−2)−(3x−2)</em>
<em>Factoring the highest common denominator 3x−2.</em>
(3x−2)(4x−1)
Use the Pythagorean Theorem: .
So your straight line distance is 10.
We can also recognize this as a multiple of the 3-4-5 Pythagorean triple. We have , with x being the desired value. Therefore x=10, like previously.
Answer: 1/x + 7
Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)
G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
