Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Answer:
Step-by-step explanation:
22
The answer would be -0.102564 repeating because if you do the math before dividing you would get -8/6.5/-1.5/-8
Okay. You can decompose 749 with these ways:
700 + 40 + 9
or
500 + 200 + 40 + 9
Does the relation {(-2,2), (-7,1), (-3,9), (-8,4), (-9,5), (-6,8)) represent
Gelneren [198K]
Answer:
Yes
Step-by-step explanation:
This does represent a function because every x-value only goes to one y-value.
