The sum of the given series can be found by simplification of the number
of terms in the series.
- A is approximately <u>2020.022</u>
Reasons:
The given sequence is presented as follows;
A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021
Therefore;
The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;
Therefore, for the last term we have;
2 × 2043231 = n² + 3·n + 2
Which gives;
n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0
Which gives, the number of terms, n = 2020


Which gives;


Learn more about the sum of a series here:
brainly.com/question/190295
Answer:
Step-by-step explanation:
4.75 x 
What is the 9th term of the geometric sequence 4, -20, 100, ...
<span>First term, a = 4 </span>
<span>common ratio, r = –20 / 4 = –5 </span>
<span>..... ..... ..... ..... = 100 / –20 = –5 </span>
<span>9th term = 4 ( –5 ) ^ ( 9 - 1 ) </span>
<span>..... ...... = 4 ( –5 ) ^ 8 </span>
<span>..... ...... = 4 ( 390,625 ) </span>
<span>..... ...... = 1,562,500 </span>
5 students scored a 90 or above. If you look at the axis that says “test scores” just count the number of dots on the “90” line and above