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2 years ago

Please Help!! f(x) = square root of x plus 7 ; g(x) = 8x -11 Find f(g(x))

Mathematics

1 answer:

Sonja [21]2 years ago

8 0

I'm not sure if you mean ( $\sqrt{x + 7}$ ) or ( $\sqrt{x} + 7$ ) I solved it both ways .

$f(x) = \sqrt{x + 7} \\ \\ f( \: g(x) \: ) = \sqrt{(8x - 11)+ 7} \\ = \sqrt{8x - 11 + 7} \\ = \sqrt{8x - 4} \\ = 2 \sqrt{2x - 1}$

____o_____o______

$f(x) = \sqrt{x} + 7 \\ \\ f( \: g(x) \: ) = \sqrt{(8x - 11)} + 7 \\ = \sqrt{8x - 11} + 7\\$

I hope I helped you^_^

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Find all zeros.

Jet001 [13]

Answer:

{ 0, 3, - 3 }

Step-by-step explanation:

f(x) = x(2x - 3)(x + 3)

to find the zeros let f(x) = 0 , that is

x(2x - 3)(x + 3) = 0

equate each factor to zero and solve for x

x = 0

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

x + 3 = 0 ⇒ x = - 3

zeros are { 0, $\frac{3}{2}$ , - 3 }

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7 months ago

If sally has 566 books but has 5 box’s how many books goes into each box?

Bogdan [553]

All we have to do here is divide how many books she has (566) by how many boxes she has (5)

566 ÷ 5 = 113.2

We can round 113.2 to 113

Therefore about 113 books will be in each box

Hope this helps

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2 years ago

Read 2 more answers

Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the

adoni [48]

Answer:

45.55 meters

Step-by-step explanation:

I'm guessing she recorded above her height, right?

To find the height of the dam, use the tangent ratio:

$tangentX=\frac{opposite}{adjacent}$

The height of the dam is the side opposite the given angle, and this will represent x. The adjacent side (the hypotenuse is NEVER considered the adjacent side) is the distance from Scarlett to the dam. The angle of elevation is the angle of 26°. Insert the values:

$tan26=\frac{x}{90}$

Solve for x. Multiply both sides by 90:

$90*(tan26)=90*(\frac{x}{90})\\\\90*tan26=x$

Insert equation into a calculator:

$x=90*tan26\\\\x=43.9$

Now add Scarlett's height:

$43.9+1.65=45.55$

The dam is 45.55 meters tall.

<em>Finito</em> :D

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3 years ago

Change at least one number in the table so that it DOES represent a function.

almond37 [142]

Answer:

change 2 to 4

and 1 to 5

1 --> 5

2 --> 10

3 --> 15

4 --> 20

5 --> 24

Step-by-step explanation:

Function means you can have one input for evry one output

so you have to change the 2 and 1 to diffrent numbers like 4 and 5

so now evey imput has their own out put

befor input one it had 5 and 24

and input two had 10 and 20 but changing the number you get one for one

6 0

2 years ago

A student in wildlife management studied trout habitat in the upper Shavers Fork watershed in West Virginia. The springtime wate

nataly862011 [7]

Answer:

C. H 0 : μ = 7 vs. Ha : μ ≠ 7

Since the calculated value of t = -9.462 falls in the critical region t ≤-2.048

We conclude that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

Step-by-step explanation:

The null hypothesis the usually the test to be performed. Here we want to check whether the water is neutral or not. Neutral water must have a pH of 7 . This can be stated as the null hypothesis. And the claim is treated as the alternate hypothesis that water in not neutral or not having pH= 7

In symbols it will be written as

H0: : μ = 7 vs. Ha : μ ≠ 7

So choice C is the best option for this hypothesis testing.

Let the significance level be 0.05

The degrees of freedom = n-1= 29-1 = 28

The critical value is t ≥ 2.048 and t ≤ - 2.048 for 0.05 two tailed test with 28 df.

The test statistic to use is t- test

t= x- u/ s/√n

The total sum is 170.9 and mean = x= 5.893

The u = 7

And the sample standard deviation is =s= 0.63

Putting the values

t= 5.893-7/0.63/√29

t= - 1.107/0.11699

t= -9.4623

Since the calculated value of t = -9.462 falls in the critical region t ≤-2.048

We conclude that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

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2 years ago