2 years ago

I WILL MARK BRAINLIEST

Mathematics

1 answer:

hammer [34]2 years ago

7 0

Answer:

D. The probability is 7%.

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F(x) = 9 + 4x f(0) = f(-1) = Find the value of x for which f(x) =6 x=

puteri [66]

Answer: x=-3/4

Step-by-step explanation:

Since we know f(x)=6, we can set it equal to the equation.

6=9+4x [subtract 9 on both sides]

-3=4x [divide both sides by 4]

x=-3/4

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3 years ago

Jasmine believe the lengths 7 in 12 in and 20 inch will form a triangle is Jasmine correct use mathematics or words to explain y

madreJ [45]

Answer:

7 in 12 30 inch jasmine correct is triangle

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1 year ago

How do I solve the equation 2x-5x+6.3=-14.4

Serga [27]

-3x+6.3=-14.4
-6.3=-6.3
-3x=-20.7
-3 -3
x=6.9

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3 years ago

How do I solve the linear equation of 27=6(x)+4(y) over 20=2(x)+5(y)

larisa86 [58]

27 = 6x + 4y = 1 7/20 = 3 4/5
20 = 2x + 5y

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3 years ago

What is the area of the sector ?

worty [1.4K]

They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first. By the Law of Cosines

$x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ$

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,

$x^2 = 9^2 + 9^2 - 2(9)(9) \cos B$

$x^2 = 162 - 162 \cos B$

$\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}$

$\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}$

$B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)$

The area of the circle is the fraction given by the angle,

$A = \dfrac{B}{360^\circ} \pi r ^2$

$A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2$

$A\approx 24.7474332960707$

Answer: 24.7 sq cm

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2 years ago