Answer: Choice C
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
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Explanation:
Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.
Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.
Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.
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In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.
Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.
Answer:
1250 
Step-by-step explanation:
We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.
Let the length of the rectangle be 'X' feet and width be 'Y' feet.
As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.
As, X + 2Y = 100 → X = 100 - 2Y
Now, the area of the rectangle = XY = X × ( 100 - 2Y ).
i.e Area of the rectangle =
.
The general form of a quadratic equation is
.
The maximum value of a quadratic equation is given by
.
Therefore, the greatest value of
is at Y =
=
= 25.
Thus, Y = 25 and X = 100 - 2Y → X = 100 - 2 × 25 → X = 50.
Hence, the area of the rectangle is XY = 50 × 25 = 1250
.
Answer: (2,2), (4,2)
First, I subtracted 2y from both sides of the second equation. Then, I substituted -2y+6 in for x in the first equation (-2y+6)²+4y²=20. Then, I expanded 4y²-24y+16+4y²=20. Next, I combined like terms, and moved everything to one side 8y²-24y+16=0. Then, I factored out an 8, and then finished factoring 8(y-2)(y-1). This gives me my y-values, y=1,2. Next, I inserted each y-value into the second equation and got x=-2(1)+6 ---> x=4 (The first solution is (4,1). ) and x=-2(2)+6----->x=2 (The second solution is (2,2).
She should invest $6491.73.
The equation we use to solve this is in the form

,
where A is the total amount in the account, p is the principal invested, r is the interest rate as a decimal, n is the number of times per year the interest is compounded, and t is the amount of time.
A in our problem is 14000.
p is unknown.
r is 6% = 6/100 = 0.06.
n is 2, since it is compounded semiannually.
t is 13.