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Vika [28.1K]
3 years ago
14

What is the place the 8 is in in the number 38,341,097.54

Mathematics
1 answer:
Sophie [7]3 years ago
4 0
It’s in the Millions place
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In Neil's city, the temperature is 72.6 degrees and is rising 1.3 degrees each hour. In Sheppard's city, the temperature is 80.4
klio [65]

Answer:

2.5 hours

Step-by-step explanation:

Given that :

Temperature in Neil's city :

72.6° and rising by 1.3° per hour

Temperature in Sheppard's city :

80.4° and dropping by 1.82° per hour

In how many hours will the temperature in Neil's city be no less than the temperature in Sheppard's city

Let number of hours = h

Hence, Neil city :

72.6 + 1.3h

Sheppard city:

80.4 - 1.82h

72.6 + 1.3h ≥ 80.4 - 1.82h

1.3h + 1.82h ≥ 80.4 - 72.6

3.12h ≥ 7.8

h ≥ 2.5

Two and half hours (2 hours 30 minutes)

8 0
3 years ago
What is the missing number ? <br> 1,8,27,64,125,216,?
Katena32 [7]

Answer:

64

Step-by-step explanation:

this is the sequence of cube. ... hence the sequence will be 1-8-27-64-125-216.

(wen 64 is already tere)

3 0
3 years ago
Which function passes through the points (2, 15) and (3, 26)?
igor_vitrenko [27]
<span>Which function passes through the points (2, 15) and (3, 26)?
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Its B
7 0
3 years ago
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Which equation represents the relationship "3 more than a number is 7"
Reika [66]
3+x=7Becayse you get the three and add it to a variable equals 7
7 0
3 years ago
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Suppose that contamination particle size (in micrometers) canbe modeled as
asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1

a) probability density function.

\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1

Thus, it is a probability density function.

b) cumulative distribution function.

P(X

c) mean of the distribution

\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2

d) probability that the size of random particle will be less than 5 micrometers

P(X

4 0
3 years ago
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