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3 years ago

Original price: $330 discount percent: 15%

Mathematics

2 answers:

yuradex [85]3 years ago

7 0

Answer:

$280.5

Step-by-step explanation:

Anastaziya [24]3 years ago

4 0

Answer:

$280.5

is the answer <3

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Pls help me with this

OlgaM077 [116]

Answer:

1/(x^(17/12)y^(5/3))

Step-by-step explanation:

We assume you want to simplify the expression. The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

1/a^b = a^-b

Using these "all at once", we can add up the exponents of each of the variables:

x^(-2/3 -2·0 -(1/2)(3/2))·y^(-2/3-(1/2)·2) = x^(-2/3-3/4)y^(-2/3-1)

= x^(-17/12)y^(-5/3)

= $\dfrac{1}{x^{\frac{17}{12}}y^{\frac{5}{3}}}$

4 0

4 years ago

Find the coordinates of point S On QR such that the ratio of QS to SR is 1:3 Q(2,5) R(-2,-3)

Roman55 [17]

Answer:

slope or what y2-y1/x2-x1 use the formula

6 0

4 years ago

What is the ratio for 8 and 12

Vitek1552 [10]

It can be 8:12 or as a fraction it’s 8/12

5 0

3 years ago

16 = s/2 *

emmainna [20.7K]

Step-by-step explanation:

x+8=10

x−4=22

x÷3=6

7x=28

60=30+30=6+6+6+6+6+6+6+6+6+6

a=a

a=b,thenb=a

60=30+30,then30+30=60

ifa=bandb=c,thena=c

60=30+30

30+30=6+6+6+6+6+6+6+6+6+6

60=6+6+6+6+6+6+6+6+6+6

4 0

3 years ago

Read 2 more answers

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

3 years ago