The product of a number y and 12 or 12 times a number y. These are both equivalent expressions to 12y
Answer: There are approximately 853827 new cases in 6 years.
Step-by-step explanation:
Since we have given that
Initial population = 570000
Rate at which population decreases is given by

Now,
First year =570000
Second year is given by

Third year is given by

so, there is common ratio ,
it becomes geometric progression, as there is exponential decline.
so,

a=570000
common ratio is given by

number of terms = 6
Sum of terms will be given by

We'll put this value in this formula,

So, there are approximately 853827 new cases in 6 years.
Can not be simplify
Step-by-step explanation:
One root is 1.0791561975888, the other is -0.57915619758885.