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3 years ago

This is the one i am stuck on

Mathematics

2 answers:

nasty-shy [4]3 years ago

7 0

16/4=4
So there are 4 black beads
8+8=16
16=4/5
4/5 divided by 2=4/10=2/5
So the probability of green and yellow is 2/5

Sveta_85 [38]3 years ago

7 0

Answer:

yeah what he said, THE ONE ABOVE ME.

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Find the vertex of the graph of the function. f(x) = 2x2 - 8x + 9

Katen [24]

Answer:

(2, 1).

Step-by-step explanation:

f(x)=2x^2-8x+9

Find -b/2a first, it's -(-8)/2(2)=8/4=2.

Then find the y-coordinate of the vertex.

2(2)^2-8(2)+9=2(4)-16+9=8-16+9=-8+9=1

8 0

4 years ago

Solve the equation. x2 18x 81 = 25 a. 14, 4 b. –4, –14 c. 14, –14 d. –4, 4

Snowcat [4.5K]

Answer:

The answer is the option B

$-4,-14$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}+18x+81=25$

$x^{2}+18x+56=0$

$a=1\\b=18\\c=56$

substitute in the formula

$x=\frac{-18(+/-)\sqrt{18^{2}-4(1)(56)}} {2(1)}$

$x=\frac{-18(+/-)\sqrt{100}} {2}$

$x=\frac{-18(+/-)10} {2}$

$x1=\frac{-18+10} {2}=-4$

$x2=\frac{-18-10} {2}=-14$

7 0

4 years ago

Read 2 more answers

Asif wants to rewrite 28+49 using the greatest common factor and the distributive property

Papessa [141]

Answer:

Step-by-step explanation:

28 = 7 *4

49 = 7 * 7

GCF = 7

28 + 49 = (7*4) + (7*7)

= 7*(4 + 7)

5 0

3 years ago

1/4 times 7/8 please help me with this question I’m so confused

Alexeev081 [22]

You basically multiply across. 1/4 times 7/8 is 7/32 because numerator, 1 times 7 and denominator, 4 times 8. Hope it helps.

8 0

3 years ago

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Indefinite integral need help pleaseeeeeee

tatiyna

Integrate indefinite integral:
$I=\int\frac{dx}{e^{2x}+3e^x+2}dx$

Solution:
1. use substitution $u=e^x$
=>
$du=e^xdx$
=>
$dx=\frac{du}{e^x}$
=>
$dx=\frac{du}{u}$
=>
$I=\int\frac{du}{u(u^2+3u+2)}du$
$=\int\frac{du}{u(u+2)(u+1)}du$
2. decompose into partial fractions
$\frac{1}{u(u+2)(u+1)}$
$=\frac{A}{u}+\frac{B}{u+2}+\frac{C}{u+1}$
where A=1/2, B=1/2, C=-1
$=\frac{1}{2u}+\frac{1}{2(u+2)}-\frac{1}{u+1}$
3. Substitute partial fractions and continue
$I=\int\frac{du}{2u}+\int\frac{du}{2(u+2)}-\int\frac{du}{u+1}$
$=\frac{log(u)}{2}+\frac{log(u+2)}{2}-log(u+1)}$
4. back-substitute u=e^x
$=\frac{log(e^x)}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}$
$=\frac{x}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}$

Note: log(x) stands for natural log, and NOT log10(x)

7 0

3 years ago