The ticket price that would maximize the total revenue would be $ 23.
Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:
- 20,000 x 30 + 20,000 x 8 = 760,000
- 24,000 x 25 + 24,000 x 8 = 792,000
- 28,000 x 20 + 28,000 x 8 = 784,000
- 26,000 x 22.5 + 26,000 x 8 = 793,000
- 27,200 x 21 + 27,200 x 8 = 788,000
- 26,400 x 22 + 26,400 x 8 = 792,000
- 25,600 x 23 + 25,600 x 8 = 793,600
- 24,800 x 24 + 24,600 x 8 = 792,000
Therefore, the ticket price that would maximize the total revenue would be $ 23.
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Answer:
400 mL
Step-by-step explanation:
0.50x + 0.20(600-x) = 0.40*600
50x + 20*600 - 20x = 40*600
30x = 20*600
x = 20*20
x = 400 mL
Answer:
q.4 's answer is d. miles
q.5 's answer is 3
q.6 's answer is 6
can you tell what the dot means i can tell you the other two's too
To a higher number the six changes value in this number above
