16^.5 =4
1/2 power is the same as square root
So y = 4x
Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


Hope you are having a great day!
STEP BY STEP: a+b(x)=6
Answer:
15 miles
Step-by-step explanation:
8.80-2.80=6
6/0.40=15 miles
2/3(6x+3)
2/3 x 3(2x+1)
2(2x+1)
4x+2
Therefore your answer is 4x+2