Answer:
Step 4
Step-by-step explanation:
Tasha was correct in all the steps leading up to the fourth one. However, in the fourth step was where she messed up.
She said that: 
However, when we have a negative exponent, in order to get rid of the negative, we simply take the reciprocal of the number and then make the exponent positive. Here, the answer should be:
Answer:
(1,2021)
Step-by-step explanation:
P and q can vary subject to their sum being 2020.
Consider one parabola with p1 and q1 and another with p2 and q2.
y1=(x1)^2+(p1)(x1)+(q1)
y1=(x2)^2+(p2)(x2)+(q2)
At their intersection, the x and y coordinates are the same.
y1=y2=y
x1=x2=x
x^2+(p1)x+(q1)=x^2+(p2)x+(q2)
Solve for x
x(p1-p2)=q2-q1
x=(q2-q1)/(p1-p2)
Use the constraint that p+q=2020 to eliminate p1 and p2.
p1=2020-q1
p2=2020-q2
x=(q2-q1)/(2020-q1-2020+q2)
x=(q2-q1)/(q2-q1)
x=1
Substitute in the equation for y.
y=1^2+p(1)+q
y=2021
Answer:
7/10-44/100 70-44
100
=26/100
=13/50
Step-by-step explanation:
Answer:
C cuz the propotional increases over time
Step-by-step explanation:
Easy just think of it as 30 and 3
The absolute value of a number is its distance from zero. There can not be a negative distance from zero. Therefore, all absolute values are positive, no matter if the value inside them is positive or negative. So, B, C, and D can each be the absolute value of some number x, because they are all positive.
Hope this helps! :)
