Answer:
(5,-5)
Step-by-step explanation:
Hi there!
We are given this system of equations:
2x-3y=25
5x+3y=10
and the question asks to solve it by elimination
To solve by elimination, we will add the equations together to clear one variable, solve for the variable that wasn't cleared, then use the value of the variable that wasn't cleared to solve for the variable that was cleared earlier
Before we clear a variable, the coefficients in front of the variable that we want to clear need to be opposites (ex. if we wanted to clear x, the coefficients of x in the systems have to be -2 and 2, as that would equal 0).
In this case, the coefficients in front of y in the equations are -3 and 3 respectively. That equals 0, so y would be cleared if we added the equations together
so we don't have to multiply or divide by anything prior to clearing
Let's add the equations together. Remember that y will be cleared, as (-3y+3y=0)
2x-3y=25
+
5x+3y=10
______________
7x+0=35
subtract 0 from both sides
7x=35
divide both sides by 7
x=5
we found the value of x
now we need to find the value of y
substitute 5 as x into either one of the equations to solve for y
if we were to do it into 2x-3y=25 for instance,
2(5)-3y=25
multiply
10-3y=25
subtract 10 from both sides
-3y=15
divide both sides by -3
y=-5
So the answer is x=5, y=-5, or as point<u> (5,-5)</u>
Hope this helps! :)
