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garik1379 [7]
2 years ago
12

Which of the following could represent the unit side lengths of a right triangle

Mathematics
2 answers:
svetoff [14.1K]2 years ago
6 0

Answer:

<em>Answer: D 12,16,20</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

On a right triangle with side lengths of a,b, and c, being c the hypotenuse, of the longest side, it follows that:

a^2+b^2=c^2

The set {a,b,c} is often called a Pythagorean Triple.

Testing every option:

A

5^2+8^2=10^2

25+64 = 100

89 = 100

Since equality is false, 5,8,10 are not the side lengths of a right triangle.

B

3^2+5^2=7^2

9+25 = 49

34 = 49

Since equality is false, 3,5,7 are not the side lengths of a right triangle.

C

6^2+11^2=13^2

36+121 = 169

157 = 169

Since equality is false, 6,11,13 are not the side lengths of a right triangle.

D

12^2+16^2=20^2

144+256 = 400

400 = 400

Since equality is true, 12,16,20 could be the side lengths of a right triangle.

Answer: D 12,16,20

snow_lady [41]2 years ago
4 0

Answer:

Choice D

Step-by-step explanation:

If you check each one plugging in your info into this you can get a^{2} +b^{2} =c^{2} that 12² + 16² will equal 400 which is the same as 20².

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6. Find the function with x-intercepts (-3,0) and (5,0), which also goes through the point (1,8)
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Answer:

f(x) = (-1/2)(x^2 + 8x - 15)

Step-by-step explanation:

This function has two roots:  -3 and 5.  Most likely it is a quadratic (all of which have two roots).

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The graph goes through (1. 8):  Therefore, y = 8 when x = 1:

f(1) = a(1 + 3)(1 - 5) = 8, or

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Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or

                                                        f(x) = (-1/2)(x^2 + 8x - 15)

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The measure of two supplementary angels, s and t, are the ratio of 7:3. Find the value of s
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I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know
azamat

By definition of conditional probability,

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}

=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}

Assuming a standard 6-sided fair die,

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Both outcomes are mutually exclusive with probability \frac1{36} each, hence total probability \frac2{36}=\frac1{18}.

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

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and so a sum of 7 occurs \frac6{36}=\frac16 of the time.

Then the probability we want is

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13

6 0
3 years ago
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