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garik1379 [7]
2 years ago
12

Which of the following could represent the unit side lengths of a right triangle

Mathematics
2 answers:
svetoff [14.1K]2 years ago
6 0

Answer:

<em>Answer: D 12,16,20</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

On a right triangle with side lengths of a,b, and c, being c the hypotenuse, of the longest side, it follows that:

a^2+b^2=c^2

The set {a,b,c} is often called a Pythagorean Triple.

Testing every option:

A

5^2+8^2=10^2

25+64 = 100

89 = 100

Since equality is false, 5,8,10 are not the side lengths of a right triangle.

B

3^2+5^2=7^2

9+25 = 49

34 = 49

Since equality is false, 3,5,7 are not the side lengths of a right triangle.

C

6^2+11^2=13^2

36+121 = 169

157 = 169

Since equality is false, 6,11,13 are not the side lengths of a right triangle.

D

12^2+16^2=20^2

144+256 = 400

400 = 400

Since equality is true, 12,16,20 could be the side lengths of a right triangle.

Answer: D 12,16,20

snow_lady [41]2 years ago
4 0

Answer:

Choice D

Step-by-step explanation:

If you check each one plugging in your info into this you can get a^{2} +b^{2} =c^{2} that 12² + 16² will equal 400 which is the same as 20².

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Need help with this please ​
antoniya [11.8K]

Answer:

These are kinda tuff  Mandi,  sooo remember what's below

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

now fine one of the above functions that has the 3 things you are working with.   2 knowns, and 1 unknown

also we know that the angle at the right tip of the triangle is 90-59= 31°

we know that b/c the inside angles of a triangle always add to 180 and there is already a 90° so we only have 80 left, which the 59° is part of, so 31 is the other, now put that info into one of the above formulas

x= adjacent side

and we know the angle and hypotenuse side.    find the formula with those parts.  I see Cos  has those or CAH... to help remember how those fit

Cos(31) = x / 17

17*cos(31) = x

14.5718 = x

there is your answer,  understand how I got it? :)

4 0
3 years ago
The cheerleading squad at springfield high school had 20 memebers with the old coach now with the new coach there are 15 members
Vlad1618 [11]
25% decrease.
first let’s find how many have stayed. to do this, you will do,
15
—
20
which can be simplified to

3
—
4

because both can be divided by 5. but these are the people that stayed, were trying to find how many left. so, we will resort to our left over

1
—
4

which, in decimal form, is 0.25.
so, the squads size decreased by 25%
:)
4 0
2 years ago
Kevin and Randy Muise have a jar containing 56 ​coins, all of which are either quarters or nickels. The total value of the coins
fgiga [73]

Answer:

the answer would be 39 nickels and 17 quarters

Step-by-step explanation:

i did guess and check so i will just give the answer and the work for it

4.25/.25=17 quarters

56-17=39

39*.05=1.95

1.95+4.25=6.20

7 0
3 years ago
Read 2 more answers
Lois Snell reserved a $350 television set in layaway by putting down a deposit of $35. a service charge of $15 was added to the
Fed [463]
In 11 months, Lois Snell will have the television set all to herself. I found this by first taking the amount of the television set($350) and subtracting her deposit of ($35) which got me to $315. The I took $315 and added the charge which was ($15) and I got $330. Finally I took the unit price of $30 a month and divided it by the total of $330 and I got an answer of 11 months.
6 0
3 years ago
PLEASE HELP!! WILL GIVE BRAINLIEST
yarga [219]

Answer:

The graphs shown is NOT a function.

Step-by-step explanation:

We can use Vertical Line test to determine whether a given relation in the graph is a function or not. A relation is a function if one input results in only one output. If we draw vertical lines on the graph, and any of these vertical line intersect the graph at 2 or more positions, then it means that for one value of x, there are 2 values of y. Hence, for one input, there are more than one outputs. Therefore, the relation will not be a function.

We can see in the attached graph below that any vertical line intersects the graph at 2 positions. Hence, the given relation is graph is not a function.

Apologies for the rough drawing.

You can apply the same technique for the graph of the relation which is not shown, you'll get your answers to fill in the blanks

6 0
3 years ago
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