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Rasek [7]
3 years ago
6

A pole that is 3.2m tall casts a shadow that is 1.66m long. at the same time a nearby tower cast a shadow that is 39.5 m long. h

ow tall is the tower?
Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

76.14 m

Step-by-step explanation:

create a proportion of height/shadow equals height/shadow

3.2/1.66 = h/39.5

cross-multiply:

1.66h = 39.5(3.2)

1.66h = 126.4

h = 76.14

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Can someone please help me answer this because it is due in a couple of minutes. Please help
Mama L [17]

Answer:

X=-2

Step-by-step explanation:

Hope it helps

4 0
3 years ago
The distance between Frankfurt and Prague is 432.5 km. Alex left Frankfurt at 10 AM and started traveling to Prague at 60 km/h.
viva [34]

Answer:

He was already 120 km away from Frankfurt so they will meet at 120 + 150 = 370 km away from Frankfurt

Step-by-step explanation:

We are given that the distance between Frankfurt and Prague is 432.5 km.

Distance bw Frankfurt and prague, s(F&P) = 432.5km

Alex left Frankfurt at 10 AM and tavelled at 60 km/hr. At noon i.e 12 PM Michael started traveling from Prague to Frankfurt, which means that Alex travelled 2 hour before Michael started, so lets calculate that distance first.

At 10 AM:

Time travelled by Alex, t = 2hr

Speed, v = 60km/hr

Distance, s(Alex) = v × t = 60 × 2 = 120 km

At noon 12 PM:

Now that Alex has covered 120 km from Frankfurt, he is now 432.5 - 120 = 312.5 km away from Michael at 12 PM.

Distance between Michael and Alex is now 312.5 km

Now Micahel will start moving towards Frankfurt at a speed of 65km/hr

And Alex is also coming towards Prague at a speed of 60km/hr

As they are moving toward eachother their speed will be taken as cumulative.

Speed, v = 65 + 60 = 125

Distance between the two, s = 312.5km

Time t = \frac{s}{v} = \frac{312.5}{125} = 2.5 hr


In these 2.5 hr Alex will cover a distance at 60km/hr = 2.5 * 60 = 150

He was already 120 km away from Frankfurt so they will meet at 120 + 150 = 370 km away from Frankfurt



5 0
3 years ago
The expression below is scientific notation for what number??
vitfil [10]
F because a negative exponent means the decimal moves 6 places to the left
6 0
3 years ago
Read 2 more answers
In ABC, find x.<br> A is 35°<br> B is 60°<br> C is x<br> What’s x?
Kobotan [32]

Answer:

x=25

Step-by-step explanation:

180-60=120

35+120+x=180

x=25

7 0
3 years ago
NO LINKS!!!<br><br>Please help me with parts b and c. ​
bekas [8.4K]

9514 1404 393

Answer:

  b.  A × B = GCF(A, B) × LCM(A, B)

  c. 15 = GCF × LCM / 20

Step-by-step explanation:

b. The products of the numbers in the table are 80, 108, 216, 45.

The products of the corresponding GCF and LCM are 80, 108, 216, 45.

Conjecture: the product of the numbers is equal to the product of the GCF and LCM.

__

c. GCF×LCM = 5×60 = 300 = A×B = 20×B

  B = 300/20 = 15

The other number is 15, found by using the conjecture of part b.

_____

<h3><em>Additional comment</em></h3>

If you think for a minute about what the GCF and LCM are, you realize the relationship discussed in this problem must be the case. Consider the factors of two numbers A and B:

  A = (factors in common with B) × (factors unique to A)

  B = (factors in common with A) × (factors unique to B)

The GCF, by definition, are (factors in common between A and B).

The LCM, by definition, is the product of unique factors:

  (common factors) × (factors unique to A) × (factors unique to B)

__

Then the product of the LCM and the GCF is ...

  GCF × LCM =

  (factors in common) × ((factors in common) × (unique to A) × (unique to B))

Using the associative and commutative properties of multiplication, we can rearrange this product to be ...

  ((factors in common)×(unique to A)) × ((factors in common)×(unique to B))

  = A × B

__

Personally, I use a kind of diagram to represent the factorization of A and B and their LCM and GCF:

  [unique to A (common] unique to B)

Then A = factors in [ ], and B = factors in ( ). The stuff in (common] is the GCF, and the overall product is the LCM.

Using the example of part c, this would look like [4 (5] 3), so A = 4·5 = 20 and B = 5·3 = 15. The GCF is 5, and the LCM is 4·5·3 = 60.

The end parts <em>[unique to A(</em> and <em>]unique to B)</em> can have no common factors. Any common factors must reside in the (common] part.

6 0
3 years ago
Read 2 more answers
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