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Cerrena [4.2K]
3 years ago
10

Solve - 9/2y=27/2 for y.

Mathematics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

It’s y = 3

Step-by-step explanation:

Solve for y by simplifying both sides of the equation, then isolating the variable.

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Before depositing her check, Mary’s account balance was overdrawn by $64. That’s it, it was -$64. After depositing her check, he
krok68 [10]
The answer is ankkmann
7 0
3 years ago
Find the equation of the straight line passing through the point (0,1) which is perpendicular to the line y= -2x + 2
mylen [45]

Answer:

y = 1/2x + 1

In order to evaluate a slope that is perpendicular to the given equation, you need to find the opposite reciprocal of the original slope. This means you take the original slope, flip the numerator and the denominator, and change the sign in front.

-2 ⇒ 1/2

Next, we need to substitute the information given into the point-slope formula.

The point-slope formula is:

y - y₁ = m(x - x₁)

y - 1 = 1/2(x - 0)

y - 1 = 1/2x

y = 1/2x + 1

Therefore, the line perpendicular to y = -2x + 2 is y = 1/2x + 1.

6 0
3 years ago
Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a
ZanzabumX [31]

Answer:

1) Null hypothesis:p\geq 0.41  

Alternative hypothesis:p < 0.41

2) \hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) z_{crit}=-2.33

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017  

5) z_{crit}=-1.28

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that |t_{calculated}| so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis:p\geq 0.41  

Step-by-step explanation:

Data given and notation  

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

\hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

p_o=0.41 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area:  Null hypothesis:[tex]p\geq 0.41  

Alternative hypothesis:p < 0.41

Part 2  

\hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

z_{crit}=-2.33

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017  

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

z_{crit}=-1.28

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that |t_{calculated}| so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis:p\geq 0.41  

4 0
3 years ago
I will give 30 points if u help now
Amiraneli [1.4K]

Answer:

3. x=16

4. x=51

Step-by-step explanation:

3. 3x-8=x+24

2x=32

x=16

4. 2/3(x+27)= 180-(3x-25)

2/3x+18=180-3x+25

11/3x=187

11x=561

x=51

5 0
3 years ago
Read 2 more answers
BRAINLIEST ANSWER!!!! #9 1/4 (5x+2)-1/5(x+3)=2 what’s the solution set?
Nina [5.8K]

x=2 from cross multiplying.

3 0
3 years ago
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