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Cerrena [4.2K]
3 years ago
10

Solve - 9/2y=27/2 for y.

Mathematics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

It’s y = 3

Step-by-step explanation:

Solve for y by simplifying both sides of the equation, then isolating the variable.

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At sea world San Diego kid are only allowed into the air bounce if they are between 37 and 61 inches tall they are only allowed
ss7ja [257]

Answer:

Step-by-step explanation:

a. For the Air Bounce, children must be at least 37 inches tall. If we let h denote the child's height in inches, this means h≥37. They are also not allowed to be more than 61 inches tall so h≤61. We say h≥37 and h≤61. (This can be written as a compound inequality, but that is not expected at grade 6)  

For the Tide Pool Climb, children are not allowed to be over 39 inches. Using h for the child's height, this is represented by h≤39. We should also write this as 0<h since a height cannot be zero or negative.

b. The allowable heights in inches for Air Bounce are shaded blue on the number line below (note that they include 37 inches and 61 inches). No negative numbers are included on the number line as this does not make sense for the context of height.  

   

 

The allowable heights for Tide Pool Climb are shaded purple on the number line below:

   

 

Although it is not possible for a child to be close to 0 inches tall, these numbers are shaded because they fit the inequality h≤39. No negative numbers (or 0) are plotted because they do not make sense in the context of height. So the graph shows heights satisfying 0<h and h≤39.

c. In order go on the Tide Pool Climb, a child cannot be over 39 inches in height. In order to go on the Air Bounce, a child has to be at least 37 inches tall but not more than 61 inches. So to go on both, a child must be at least 37 inches tall but not more than 39 inches: 37≤h and h≤39. These heights in inches are highlighted on the number line below:

   

 

Notice that the shaded parts of this number line are where the shaded parts of the two previous underlines overlap: this makes sense as we are looking for heights of those who can go on both rides.

              ( I hope this helps and please Rate this answer it would really mean a lot to me :) )

6 0
3 years ago
Need help finding area
Law Incorporation [45]

Answer:

135

Step-by-step explanation:

15x18/2=135

..........

5 0
3 years ago
Please help, this will just take a minute of your time ❤︎ (literally)<br>(Discriminant Worksheet)
igomit [66]

Answer:

\large\boxed{x=-\dfrac{7-\sqrt{97}}{4}\ \vee\ x=-\dfrac{7+\sqrt{97}}{4}}

Step-by-step explanation:

ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\\text{We have:}\\\\-2x^2-7x+10=4\qquad\text{subtract 4 from both sides}\\\\-2x^2-7x+6=0

a=-2,\ b=-7,\ c=6\\\\\Delta=(-7)^2-4(-2)(6)=49+48=97>0\\\\\sqrt\Delta=\sqrt{97}\\\\x=\dfrac{-(-7)\pm\sqrt{97}}{2(-2)}=\dfrac{7\pm\sqrt{97}}{-4}=-\dfrac{7\pm\sqrt{97}}{4}

6 0
3 years ago
a rectangle with width of 7 and length of 9 has a square of side length 5 cut out of it. what is the area of the rectangle after
dezoksy [38]
Area of rectangle is 7x9 which is 63
Area of the square=5x5 which is 25
So area is: 63-25=38
6 0
2 years ago
It's solving multi-step inequalities
babymother [125]
H is less than or equal to 35

Just simplify each side and solve for the variable. 
4 0
3 years ago
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