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yuradex [85]
1 year ago
15

Guys how do I solve 3x+x. PLEASE HELP!!!!!

Mathematics
2 answers:
MA_775_DIABLO [31]1 year ago
8 0
I did the math and it is 4x
Schach [20]1 year ago
3 0

Answer: 4x

Step-by-step explanation:

Combine like terms

3x + x

4x

Hope this helps!

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He polynomial of degree 5, p ( x ) p(x) has leading coefficient 1, has roots of multiplicity 2 at x = 4 x=4 and x = 0 x=0, and a
noname [10]
Root of x = 4  means (x - 4) is a factorMultiplicity of two means that (x - 4) is used twice root of x= -4 means that (x+ 4) is a factormultiplicity of 1 means it is used once so y = a (x-4) (x-4) (x + 4)y = a (x^3 - 4x2 - 16x + 64)
Thus, any polynomial with these zeroans d as a minimum these multiplicities will be a multiple (scalar or polynomial) of this P(x).
3 0
4 years ago
What is the slope of any line parallel to the line 2x-3y=7?
DENIUS [597]

Rewrite 2x-3y=7 in slope-intercept is y=2/3x-7/3, and y=mx+b and m is the slope so m=2/3.

5 0
3 years ago
Read 2 more answers
Help me on this question, I'll give brainlist for the correct answer.
german

Answer:

Step-by-step explanation:

The first expression has value 12

The second expression has value -6

The third expression has value

4

And finally the forth expression has value 1.14

((13 + 7) = 20

(12+4) = 16

16/ (20 - 16)= 16 / 4

16/4 = 4

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME! THANK YOU :D
Lemur [1.5K]

Answer:

15 cm ft²

Step-by-step explanation:

need ko po that are many means

3 0
3 years ago
The duration of 5700 years is referred to as the "half-life" of carbon-14 because the amount of carbon-14 drops in half 5700 yea
alexira [117]

Answer:

Step-by-step explanation:

Given:

Carbon-14

t1/2 = 5700 years

t1 = 11400 years

t2 = 17100 years

N(t) = No(1/2)^(t/t1/2)

Where,

N(t) = amount of carbon left at time, t

No = initial amount of carbon

t = time taken

t1/2 = half life

Assume No = 1

N(11400) = 1 × (1/2)^(11400/5700)

= (1/2)^2

= 1/4

N(17100) = 1 × (1/2)^(17100/5700)

= (1/2)^3

= 1/8

From the fractions got from N(11400) and N(17100), 1/4 and 1/8 we can see a decrease in the initial amount of carbon by 1/2.

B.

t1/2 = 80000 years

N(t) = No × (1/2)^(t/80000)

Assume No = 1

N(t) = 1 × (1/2)^(t/80000)

7 0
3 years ago
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