Let x = the first number
y = the second number
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First: set up the equations.
Four times a first number: 4x
Decreased by a second number: - y
Is 4: = 4
4x - y = 4.
The first number increased by: x +
three times the second number: 3y
is -25: = -25
x + 3y = -25.
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You can make your system of equations now.
4x - y = 4
x + 3y = -25
I would use substitution to solve these.
To do substitution, isolate a variable first, in one of the equations. I would probably isolate x in the second equation.
x + 3y = -25
x = -25 - 3y
Now, you can substitute -25 - 3y into 4x - y = 4, as x.
4x - y = 4
4(-25 - 3y) - y = 4
Now just solve for y.
-100 - 12y - y = 4
-13y = 104
y = -8
Now, you can put -8 as y into one of the original equations, I'll just use 4x - y = 4.
4x - y = 4
4x - (-8) = 4
4x + 8 = 4
4x = -4
x = -1
So the first number is -1, and the second -2.
Answer:
circle graph
Step-by-step explanation:
Remember the chain rule.
L(x)=f(g(x))
L'(x)=f'(g(x))g'(x)
take the derivative of f(g(x)). just treat them like they are variables. so you get:
h'=f'(g(x))g'(x)
now plug in your x value and evaluate:
h'(1)=f'(g(1))(g'(1))
substitute in values that you know and evaluate again
h'(1)=f'(3)(-3)
h'(1)=(-5)(-3)=15
Answer:
22x+11 is your answer
Step-by-step explanation:
(2x+1)(x+8) - (x-3)(2x+1)
(2x+1)(x+8-x+3)
(2x+1)(11)
=22x+11
