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Salsk061 [2.6K]
3 years ago
13

Plssssssssssssssssss helpppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
yarga [219]3 years ago
7 0
Mans for real said nice chrome book
monitta3 years ago
4 0
Nice chrome book man. Better than a school laptop at least.
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Pls help being timed
Alex777 [14]
The answer is B your welcome
5 0
3 years ago
Growth factors for the population of Atlanta in the past five years have been 1, 2, 3, 4 , and 5. The geometric mean is a. . b.
choli [55]

Answer:

The geometric mean of given data is approximately 2.6051

Step-by-step explanation:

We are given the following data in the question:

1, 2, 3, 4, 5.

We have to find the geometric mean.

Formula:

(a_1\times a_2\times... \times a_n)^{\frac{1}{n}}

Putting the values, we get,

\text{Geometric mean} = (1\times 2\times 3\times 4 \times 5)^{\frac{1}{5}}\\=(120)^{\frac{1}{5}} \approx 2.6051

Thus, the geometric mean of given data is approximately 2.6051

4 0
4 years ago
FREE BRAINLIST NEED HELP ASAP
Ede4ka [16]

Answer:

A)4.6 yard

Step-by-step explanation:

x^{2} +10^{2} =11^{2} \\x^{2} =21\\x=\sqrt[2]{21} \\

x≅4.6

Hoped I helped, have a nice day!

7 0
3 years ago
. Equilibrium: If the number of persons who attend the club meeting this week is X, then the number of people who will attend ne
Artyom0805 [142]

Answer:

100

Step-by-step explanation:

In economics, for a firm to earn optimum profits, it is important that it achieves a long run equilibrium. We can transfer the same to the case here that for the club to achieve optimum attendance, it must achieve long- run equilibrium attendance.

The condition for Long Run Equilibrium is that:

Club meeting attendance this week = Club meeting attendance next week

X = 80 + 0.20X

X - 0.20X = 80

X = 80/0.8

X = 100.

The long- run equilibrium attendance for this club is 100.

5 0
4 years ago
An equation for the depreciation of a car is given by y=A(1-r)t where y=current value of the car.A=original cost r=rate of depre
Ann [662]
<h3>Answer: Approximately 6.58 years old</h3>

The more accurate value is 6.57881347896059, which you can round however you need. I picked two decimal places.

==================================================

Explanation:

Let's pick a starting value of the car. It doesn't matter what the starting value, but it might help make the problem easier. Let's say A = 1000. Half of that is 1000/2 = 500.

So we want to find out how long it takes for the car's value to go from $1000 to $500 if it depreciates 10% per year.

The value of r is r = 0.10 as its the decimal form of 10%

t is the unknown number of years we want to solve for

---------------------------

y = A(1 - r)^t

500 = 1000(1 - 0.1)^t

500 = 1000(0.9)^t

1000(0.9)^t = 500

0.9^t = 500/1000

0.9^t = 0.5

log( 0.9^t ) = log( 0.5 )

t*log( 0.9 ) = log( 0.5 )

t = log( 0.5 )/log( 0.9 )

t = 6.57881347896059

Note the use of logs to help us isolate the exponent.

6 0
3 years ago
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